Question

What is the sum of $ 289 $ and $ 410 $ in number name form (i.e. in words)?
(A) Six hundred and ninety two
(B) Six hundred and eighty five
(C) Six hundred and ninety nine
(D) Six hundred and fifty four

Answer 1

Hint: In the given problem, we need to find the sum of two numbers and then we have to write that sum in number name form (that is, in words). If $ z,y $ and $ x $ are unit digit, tens digit and hundreds digit respectively of three digit number of the form $ xyz $ then the number $ xyz $ can be written as $ \left( {x \times 100} \right) + \left( {y \times 10} \right) + \left( z \right) $ . We will use this information in the given problem.

Complete step-by-step answer:
In this problem, the two numbers $ 289 $ and $ 410 $ are given. The sum of $ 289 $ and $ 410 $ can be written as $ 289 + 410 $ . Let us add these two numbers. So, we get $ 289 + 410 = 699 $ .
Here we can see that the sum of $ 289 $ and $ 410 $ is three digit numbers $ 699 $ in which $ 6 $ is hundreds digit, $ 9 $ is tens digit and $ 9 $ is unit digit. We know that If $ c,b $ and $ a $ are unit digit, tens digit and hundreds digit respectively of three digit number of the form $ abc $ then the number $ abc $ can be written as
 $ \Rightarrow \left( {a \times 100} \right) + \left( {b \times 10} \right) + \left( c \right) $ . By using this fact, the three digit number $ 699 $ can be written as
 $ \Rightarrow 699 = \left( {6 \times 100} \right) + \left( {9 \times 10} \right) + \left( 9 \right) $ . That is, $ 699 = 600 + 90 + 9 $ . That is, in words we can write $ 699 = $ Six hundred $ + $ Ninety $ + $ Nine. That is, the sum of $ 289 $ and $ 410 $ in number name form (in words) is six hundred and ninety nine.

So, the correct answer is “Option C”.

Note: Remember that the number $ 40 $ in words can be written as forty. It cannot be written as fourty. Every number can be written uniquely with digits or with words.