
Sulphide ion in alkaline solution react with solid sulfur to form polysulfide ions having formula and so on. The equilibrium constant for the formation of is and for the formation of is , both from S and . What is the equilibrium constant for the formation of from and S?
A.11
B.12
C.132
D.None of these
Answer
486.6k+ views
Hint: At first we will know what an equilibrium constant means. Once we define that we will look into the balanced equation of these and we will sort out the data given in the question. We will write the equations and then add the two equations to get the final equation. Now we will calculate the final equilibrium constant by multiplying the constant of those two equations.
Complete Step by step solutions:
Step1. Equilibrium constant is the value of its reaction quotient at the point where reaction can neither go backward or forward after ample time has elapsed or we can say that there is no possibility of further change. That point is called equilibrium. In general it is denoted by K.
Step2. Given in the question that is formed by S and . And the equilibrium constant is .
Here the is the equilibrium constant.
The second equation is formation of from S and , and the equilibrium constant is
The is the equilibrium constant.
We need to find the equilibrium constant of
Step3.
At first reverse the first equation. At reversing the equilibrium constant becomes the reciprocal of itself. Let it call . And then the second equation is written as it is
On addition of these reactions the ion cancels it and the final equation is
Since the equations were added then their equilibrium constant gets multiplied.
Hence we get .
Note: The position of equilibrium constant is changed if we change the concentration of something present in the mixture. According to Le Chatelier’s Principle , The equilibrium will move in the direction which will try to undo the change made in the reaction.
Complete Step by step solutions:
Step1. Equilibrium constant is the value of its reaction quotient at the point where reaction can neither go backward or forward after ample time has elapsed or we can say that there is no possibility of further change. That point is called equilibrium. In general it is denoted by K.
Step2. Given in the question that
Here the
The second equation is formation of
The
We need to find the equilibrium constant of
Step3.
At first reverse the first equation. At reversing the equilibrium constant becomes the reciprocal of itself. Let it call
On addition of these reactions the
Since the equations were added then their equilibrium constant gets multiplied.
Hence we get
Note: The position of equilibrium constant is changed if we change the concentration of something present in the mixture. According to Le Chatelier’s Principle , The equilibrium will move in the direction which will try to undo the change made in the reaction.
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What is the technique used to separate the components class 11 chemistry CBSE

Which one is a true fish A Jellyfish B Starfish C Dogfish class 11 biology CBSE

Give two reasons to justify a Water at room temperature class 11 chemistry CBSE
