Question

What should be subtracted from $\left( {\dfrac{{ - 3}}{4}} \right)$to get $\left( {\dfrac{5}{6}} \right)$ ?

Answer 1

Hint: Since in our case we have given the question in which we have to solve and find the value of x (the number which will be subtracted from $\left( {\dfrac{{ - 3}}{4}} \right)$ to get $\left( {\dfrac{5}{6}} \right)$ ) , by somewhere using equivalent equations . Equivalent equations are said to be algebraic equations that may have the same solutions if we add or subtract the same number to both sides of an equation - Left hand side or Right hand side of the equal to sign . Or we can multiply or divide the same number to both sides of an equation - Left hand side or Right hand side of the equal to sign with the method of simplification . .

Complete step by step answer:
We will make assumption by supposing the required number to be x which will be subtracted from $\left( {\dfrac{{ - 3}}{4}} \right)$ to get $\left( {\dfrac{5}{6}} \right)$ .
According to the given question , we will frame a mathematical equation and solve it .
\[
  \left( {\dfrac{{ - 3}}{4}} \right) - x = \left( {\dfrac{5}{6}} \right) \\
\Rightarrow - x = \left( {\dfrac{5}{6}} \right) - \left( {\dfrac{{ - 3}}{4}} \right) \\
 \Rightarrow - x = \left( {\dfrac{5}{6}} \right) + \left( {\dfrac{3}{4}} \right) \\
\Rightarrow - x = \dfrac{{20 + 18}}{{24}} \\
\Rightarrow - x = \dfrac{{38}}{{24}} \\
  \Rightarrow - x = \dfrac{{19}}{{12}} \\
  x = - \dfrac{{19}}{{12}} \\
 \]

Note: In equivalent equations which have identical solutions we can perform multiplication or division by the same non-zero number both L.H.S. and R.H.S. of an equation .
In an equivalent equation which has an identical solution we can raise the same odd power to both L.H.S. and R.H.S. of an equation .
Cross check the answer and always keep the final answer simplified .