Subtract $\dfrac{2}{5}$ from $\dfrac{3}{5}$ :
Answer
580.2k+ views
Hint: The above question is based on the fraction subtraction by taking LCM.
LCM is the lowest common factor of the two or more natural numbers.
Subtraction of fraction may or may not again come as a fraction itself.
Complete step-by-step solution:
Let's explain the process of taking LCM first and then we will do the calculation part of the problem.
When the fraction has two different natural numbers( we are saying natural numbers not whole numbers because the denominator of the fraction cannot be zero for the fraction to exist ), then we have broken those natural numbers into their factor. On factorization we will check which is the smallest number and is common to both the factors of the two given numbers and the uncommon numbers are multiplied with the common values.
We will learn taking LCM with an example:
Suppose we have 12 and 8 of which we have to take LCM.
$
$\Rightarrow 12 = 2 \times 3 \times 2 $
$ \Rightarrow 8 = 2 \times 2 \times 2 $
$
In the above two expressions we have common values: $2 \times 2$ and the uncommon values are $2 \times 3$ on multiplying both the terms we have,
$ \Rightarrow 2 \times 2 \times 2 \times 3 = 24$
Now, we will calculate the subtraction of fraction;
$ \Rightarrow \dfrac{3}{5} - \dfrac{2}{5}$ , we will take LCM of the denominator
Denominator has the same value 5, which is the LCM of the fraction.
$ \Rightarrow \dfrac{{3 - 2}}{5}$
$ \Rightarrow \dfrac{1}{5}$ is the value of the fraction.
$\dfrac{1}{5}$ is the required answer.
Note: When the denominator of the fraction has the same value, then the LCM of the fractions will become that number itself as we did in the question above. In case the values of the fraction is different then we have to take LCM as per the procedure we have discussed in the solution.
LCM is the lowest common factor of the two or more natural numbers.
Subtraction of fraction may or may not again come as a fraction itself.
Complete step-by-step solution:
Let's explain the process of taking LCM first and then we will do the calculation part of the problem.
When the fraction has two different natural numbers( we are saying natural numbers not whole numbers because the denominator of the fraction cannot be zero for the fraction to exist ), then we have broken those natural numbers into their factor. On factorization we will check which is the smallest number and is common to both the factors of the two given numbers and the uncommon numbers are multiplied with the common values.
We will learn taking LCM with an example:
Suppose we have 12 and 8 of which we have to take LCM.
$
$\Rightarrow 12 = 2 \times 3 \times 2 $
$ \Rightarrow 8 = 2 \times 2 \times 2 $
$
In the above two expressions we have common values: $2 \times 2$ and the uncommon values are $2 \times 3$ on multiplying both the terms we have,
$ \Rightarrow 2 \times 2 \times 2 \times 3 = 24$
Now, we will calculate the subtraction of fraction;
$ \Rightarrow \dfrac{3}{5} - \dfrac{2}{5}$ , we will take LCM of the denominator
Denominator has the same value 5, which is the LCM of the fraction.
$ \Rightarrow \dfrac{{3 - 2}}{5}$
$ \Rightarrow \dfrac{1}{5}$ is the value of the fraction.
$\dfrac{1}{5}$ is the required answer.
Note: When the denominator of the fraction has the same value, then the LCM of the fractions will become that number itself as we did in the question above. In case the values of the fraction is different then we have to take LCM as per the procedure we have discussed in the solution.
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