Answer

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**Hint:**To solve this, we need to check the statements. In statement 1, inclined length and string lengths are given from which we can derive height.

In statement 2, angle of elevation is asked and base and height are equal. From that we can derive an angle of elevation.

**Complete step-by-step answer:**

Let’s check if statement 1 is true or false.

Representing the data of statement 1 in below diagram,

Data given in the statement 1,

A kite is flying with the string inclined at $30^\circ $ to the horizon i.e.

$\sin A = 30^\circ $

String length AC = 15 meter

We have to check the height of the kite above the ground is 7.5 meter

i.e. AB = 7.5 meter

So, we have $\sin A = 30^\circ $

Hence,

$ \Rightarrow \dfrac{h}{{15}} = \sin 30^\circ $

Putting value of $\sin 30^\circ $ in it,

$\dfrac{h}{{15}} = \dfrac{1}{2}$

$ \Rightarrow h = \dfrac{{15}}{2} = 7.5$ meters

Hence the height of kite above the ground is 7.5 meters

And statement 1 is true.

Now, let’s check if statement 2 is true or false.

Representing the statement 2 in below diagram,

Let height of the pole be AB = h

According to the statement 2 height of the pole is equal to the shadow of the pole BC

Then BC = h

Let $\theta $ be the angle of elevation

According to the diagram,

$\tan \theta = \dfrac{{AB}}{{BC}}$

Putting the value of AB and BC in it we get,

$\tan \theta = \dfrac{h}{h} = 1$

Or, $\theta = {\tan ^{ - 1}}1 = 45^\circ $

Hence the angle of elevation is $45^\circ $ that means the altitude of the sun is $45^\circ $.

The statement 2 is also true.

Both statements are true.

**So, the correct answer is “Option C”.**

**Note:**The angle of elevation is the altitude of the sun.

You might make mistakes while making inverse trigonometry.

Both the statements are represented in a right angled triangle.

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