
How do you solve ${x^2} - 2x + 1 = 0$ by factoring ?
Answer
535.5k+ views
Hint: Given equation is of degree $2$. Equations of degree $2$ are known as quadratic equations. Quadratic equations can be factored by the help of splitting the middle term method. In this method, the middle term is split into two terms in such a way that the equation remains unchanged and can be factored subsequently.
Complete step-by-step solution:
For factorising the given quadratic equation ${x^2} - 2x + 1 = 0$ , we use the splitting the middle term method.
Now, we have to factorise the quadratic equation thus obtained. We can use splitting the middle term method in which the middle term is split into two terms such that the sum of the terms gives us the original middle term and product of the terms gives us the product of the constant term and coefficient of ${x^2}$.
So, ${x^2} - 2x + 1 = 0$
$ \Rightarrow {x^2} - \left( {1 + 1} \right)x + 1 = 0$
We split the middle term $ - 2x$ into two terms $ - x$ and $ - x$ since the product of these terms, ${x^2}$ is equal to the product of the constant term and coefficient of ${x^2}$ and sum of these terms gives us the original middle term, $ - 2x$.
$ \Rightarrow {x^2} - \left( {1 + 1} \right)x + 1 = 0$
Opening the bracket and simplifying the expression,
$ \Rightarrow {x^2} - x - x + 1 = 0$
Taking out x common from first two terms and negative sign common from the last two terms,
$ \Rightarrow x\left( {x - 1} \right) - \left( {x - 1} \right) = 0$
$ \Rightarrow \left( {x - 1} \right)\left( {x - 1} \right) = 0$
$ \Rightarrow $${\left( {x - 1} \right)^2} = 0$
So, the factored form of the equation ${x^2} - 2x + 1 = 0$ is ${\left( {x - 1} \right)^2} = 0$.
Note: Splitting of the middle term can be a tedious process at times when the product of the constant term and coefficient of ${x^2}$ is a large number with a large number of divisors. Special care should be taken in such cases. Similar to quadratic polynomials, quadratic solutions can also be solved using factorisation method. Besides factorisation, there are various methods to solve quadratic equations such as completing the square method and using the Quadratic formula.
Complete step-by-step solution:
For factorising the given quadratic equation ${x^2} - 2x + 1 = 0$ , we use the splitting the middle term method.
Now, we have to factorise the quadratic equation thus obtained. We can use splitting the middle term method in which the middle term is split into two terms such that the sum of the terms gives us the original middle term and product of the terms gives us the product of the constant term and coefficient of ${x^2}$.
So, ${x^2} - 2x + 1 = 0$
$ \Rightarrow {x^2} - \left( {1 + 1} \right)x + 1 = 0$
We split the middle term $ - 2x$ into two terms $ - x$ and $ - x$ since the product of these terms, ${x^2}$ is equal to the product of the constant term and coefficient of ${x^2}$ and sum of these terms gives us the original middle term, $ - 2x$.
$ \Rightarrow {x^2} - \left( {1 + 1} \right)x + 1 = 0$
Opening the bracket and simplifying the expression,
$ \Rightarrow {x^2} - x - x + 1 = 0$
Taking out x common from first two terms and negative sign common from the last two terms,
$ \Rightarrow x\left( {x - 1} \right) - \left( {x - 1} \right) = 0$
$ \Rightarrow \left( {x - 1} \right)\left( {x - 1} \right) = 0$
$ \Rightarrow $${\left( {x - 1} \right)^2} = 0$
So, the factored form of the equation ${x^2} - 2x + 1 = 0$ is ${\left( {x - 1} \right)^2} = 0$.
Note: Splitting of the middle term can be a tedious process at times when the product of the constant term and coefficient of ${x^2}$ is a large number with a large number of divisors. Special care should be taken in such cases. Similar to quadratic polynomials, quadratic solutions can also be solved using factorisation method. Besides factorisation, there are various methods to solve quadratic equations such as completing the square method and using the Quadratic formula.
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