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Solve the following equations:
a). $2y+\dfrac{5}{2}=\dfrac{37}{2}$
b). $5t+28=10$

Last updated date: 13th Jul 2024
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Hint: According to the given question, we need to solve the given equations in one unknown variable, that is we need to find the value of the unknown in all the parts of the question. All we need to do is keep the unknowns on one side and the constants on one side and then simplify.

Complete step-by-step solution:
According to the question, we are having two equations which we need to solve. Now in order to solve we will proceed in the following way:
For part (a): $2y+\dfrac{5}{2}=\dfrac{37}{2}$
Now, what we will do is we will keep the constants on one side as
  & 2y+\dfrac{5}{2}=\dfrac{37}{2} \\
 & \Rightarrow 2y=\dfrac{37}{2}-\dfrac{5}{2} \\
 & \Rightarrow 2y=\dfrac{32}{2} \\
 & \Rightarrow 2y=16 \\
Now, we have simplified it but we can see that we can simplify it further, so for that we will make the coefficients of y as 1 which implies $y=8$ .
Similarly, for the next part we have the equation as $5t+28=10$.
Now, simplifying this we will get
  & 5t=10-28 \\
 & \Rightarrow 5t=-18 \\
Now, again making the coefficients of t as 1 we will get, $t=\dfrac{-18}{5}$
Therefore, we can clearly see that the value of y is 8 and value of t is $-\dfrac{18}{5}$.

Note: In such types of questions, we need to be careful during the calculations and then we need to simplify them. Also, we need to keep in mind that we need to keep constants on one side in order to reduce the calculation error.