Solve the following equation:
\[5r + 28 = 10\]
Last updated date: 19th Mar 2023
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Answer
308.7k+ views
Hint:- Take constant terms on one side of the equation.
As, we are given the equation,
\[ \Rightarrow 5r + 28 = 10\] (1)
As, we can see from the above equation that the given equation has only one variable.
So, whenever we are given with one equation having one variable then we will find the
value of variable by taking all the constant terms to one side of the equation.
So, now for solving equation 1.
Subtracting 28 to both sides of the equation 1. We get,
\[
\Rightarrow 5r = 10 - 28 \\
\Rightarrow 5r = \left( { - 14} \right) \\
\]
Now, dividing both sides of the above equation by 5. We get,
\[ \Rightarrow r = \dfrac{{\left( { - 14} \right)}}{5} = \left( { - 2.8} \right)\].
Hence the value of r will be -2.8.
Note:- In these types of questions if there are n variables in an equation then there should be
minimum of n different equations, to get the value of all variables. And easiest and efficient
way to get values of different variables is by substituting the values of variables in different
equations.
As, we are given the equation,
\[ \Rightarrow 5r + 28 = 10\] (1)
As, we can see from the above equation that the given equation has only one variable.
So, whenever we are given with one equation having one variable then we will find the
value of variable by taking all the constant terms to one side of the equation.
So, now for solving equation 1.
Subtracting 28 to both sides of the equation 1. We get,
\[
\Rightarrow 5r = 10 - 28 \\
\Rightarrow 5r = \left( { - 14} \right) \\
\]
Now, dividing both sides of the above equation by 5. We get,
\[ \Rightarrow r = \dfrac{{\left( { - 14} \right)}}{5} = \left( { - 2.8} \right)\].
Hence the value of r will be -2.8.
Note:- In these types of questions if there are n variables in an equation then there should be
minimum of n different equations, to get the value of all variables. And easiest and efficient
way to get values of different variables is by substituting the values of variables in different
equations.
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