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Solve the following $13 \div [( - 2) + 1]$

Answer
VerifiedVerified
464.7k+ views
Hint: Here we are asked to solve the given arithmetic expression. Any arithmetic expression can be solved by using the BODMAS rule. In BODMAS rule we will simplify the given expression in the particular order: Brackets, ‘of’, Division, Multiplication, Addition and Subtraction. That is, we have to first simplify the things in the brackets, then the operation “of” (if any) then the division, multiplication, addition and subtraction respectively. Here we will solve the given expression by the above rule.

Complete step by step solution:
We will make use of the simple operations and BODMAS rule to solve the given problem, Since the BODMAS rule is a rule to simplify the given problem in the format of bracket terms at first, followed by the division, multiplication, addition, and subtraction operations.
Hence, we solve the bracket terms at first $13 \div [( - 2) + 1]$ then we get $\dfrac{{13}}{{[( - 2) + 1]}} = \dfrac{{13}}{{ - 1}}$
Because using the addition and subtraction we get $ - 2 + 1 = - 1$ and thus as we mention in the hint the larger number sign stays constant. Suppose if both terms are at the same sign like $ - 2 - 1 = - 3$ then general addition is enough for it.
Thus, further solving the values with the division operation we get $\dfrac{{13}}{{ - 1}} = - 13$ (the denominator negative signs will be passed to the numerator $\dfrac{{13}}{{ - 1}} = \dfrac{{ - 13}}{1} = - 13$)
Thus, we get $13 \div [( - 2) + 1] = - 13$ is the required answer, using addition, subtraction, and division we got the simplification.

Note: In the above problem, we have to give more attention in simplifying the integers because we may tend to make mistakes there. The above problem has some operation inside the brackets that is $\left[ { - 2 + 1} \right]$ here both the terms are integers with different sign so as we know that integers with different signs will get subtracted and the answer will get the sign of the greatest number among those two numbers. So, it is important to be careful in doing these calculations.

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