
How do you solve for $ y $ in the equation $ x = y + 5 $ ?
Answer
556.2k+ views
Hint: In this question we need to find $ y $ . First we rewrite the given equation in the form of $ y + c = x $ . The variable $ y $ in the LHS (Left Hand Side). This step didn’t change anything.
Now we subtract on both sides. After subtracting we get the zero term, the zero term is vanishing.
And then finally we get the result.
Complete step by step answer:
The given equation is $ x = y + 5 $ .
Let, $ x = y + 5 $
Now, we find the $ y $
We want to rewrite this as, hence we get
$ y + 5 = x $
I didn’t change anything that’s still positive $ y $ and that’s still a positive $ 5 $ .
Now, we subtract $ 5 $ in LHS (Left Hand Side) and subtract $ 5 $ in RHS (Right Hand Side), hence we get
$ y + 5 - 5 = x - 5 $
Subtract in LHS (Left Hand Side) $ 5 $ by $ 5 $ , hence the term is zero, hence we get the equation is
$ y + 0 = x - 5 $
The zero terms are vanishing, hence we get
$ y = x - 5 $
Then the $ y $ equation is,
$ y = x - 5 $
Note: The linear equation in two variables is any first degree equation containing two variables $ x $ and $ y $ is called a linear equation in two variables.
The general form of linear equation in two variables $ x $ and $ y $ is $ ax + by + c = 0 $ , where at least one of $ a,b $ is non-zero and $ a,b,c $ are real numbers.
A system of linear equations consists of two or more linear equations made up of two or more variables, such that all equations in the system are considered simultaneously.
To find the unique solution to a system of linear equations, we must find a numerical value for each variable in the system that will satisfy all equations in the system at the same time.
Now we subtract on both sides. After subtracting we get the zero term, the zero term is vanishing.
And then finally we get the result.
Complete step by step answer:
The given equation is $ x = y + 5 $ .
Let, $ x = y + 5 $
Now, we find the $ y $
We want to rewrite this as, hence we get
$ y + 5 = x $
I didn’t change anything that’s still positive $ y $ and that’s still a positive $ 5 $ .
Now, we subtract $ 5 $ in LHS (Left Hand Side) and subtract $ 5 $ in RHS (Right Hand Side), hence we get
$ y + 5 - 5 = x - 5 $
Subtract in LHS (Left Hand Side) $ 5 $ by $ 5 $ , hence the term is zero, hence we get the equation is
$ y + 0 = x - 5 $
The zero terms are vanishing, hence we get
$ y = x - 5 $
Then the $ y $ equation is,
$ y = x - 5 $
Note: The linear equation in two variables is any first degree equation containing two variables $ x $ and $ y $ is called a linear equation in two variables.
The general form of linear equation in two variables $ x $ and $ y $ is $ ax + by + c = 0 $ , where at least one of $ a,b $ is non-zero and $ a,b,c $ are real numbers.
A system of linear equations consists of two or more linear equations made up of two or more variables, such that all equations in the system are considered simultaneously.
To find the unique solution to a system of linear equations, we must find a numerical value for each variable in the system that will satisfy all equations in the system at the same time.
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