
Solve \[8{x^2} + 21 = - 59x\].
Answer
450.9k+ views
Hint: To solve $x$ we have: $x = \dfrac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}$ from the quadratic formula.So in order to solve the above given question using a quadratic formula we have to find the values of $a,\;b,\;c$ corresponding to the given question. Then by substituting the values in the above equation we can find the values for $x$ and thereby solve it.
Complete step by step answer:
Given
\[8{x^2} + 21 = - 59x \\
\Rightarrow 8{x^2} + 59x + 21 = 0.............................\left( i \right)\]
Now we need to compare (i) to the general formula and find the values of unknowns. Then we have to use the equation to find $x$by substituting all the values needed in it and by that way we can solve the equation\[8{x^2} + 59x + 21 = 0.\].
So on comparing (i) to the general formula$a{x^2} + bx + c = 0$, we get:
$a = 8,\;b = 59,\;c = 21.....................\left( {ii} \right)$
Now to solve for $x$we have $x = \dfrac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}......................\left( {iii} \right)$
Now substituting (ii) in (iii) we get:
\[x = \dfrac{{ - \left( {59} \right) \pm \sqrt {{{\left( {59} \right)}^2} - 4\left( {8 \times 21} \right)} }}{{2 \times 8}} \\
\Rightarrow x = \dfrac{{ - 59 \pm \sqrt {\left( {3481} \right) - 4\left( {168} \right)} }}{{16}} \\
\Rightarrow x = \dfrac{{ - 59 \pm \sqrt {\left( {3481} \right) - \left( {672} \right)} }}{{16}} \\
\Rightarrow x = \dfrac{{ - 59 \pm \sqrt {\left( {2809} \right)} }}{{16}} \\
\Rightarrow x = \dfrac{{ - 59 \pm 53}}{{16}} \\ \]
Now there are two possibilities of $x$, which is produced either by addition or by subtraction. It’s found such that:
\[x = \dfrac{{ - 59 + 53}}{{16}}\;\;\;\;{\text{and}}\;\;\;x = \dfrac{{ - 59 - 53}}{{16}} \\
\Rightarrow x = - \dfrac{6}{{16}}\;\;\;\;{\text{and}}\;\;\;x = - \dfrac{{112}}{{16}} \\
\Rightarrow x = - \dfrac{{2 \times 3}}{{2 \times 8}}\;\;\;\;{\text{and}}\;\;\;x = - \dfrac{{4 \times 4 \times 7}}{{4 \times 4}} \\
\Rightarrow x = - \dfrac{3}{8}\;\;\;\;{\text{and}}\;\;\;x = - 7 \\
\therefore x = - \dfrac{3}{8},\; - 7 \\ \]
Therefore on solving \[8{x^2} + 21 = - 59x\] we get \[x = - \dfrac{3}{8},\; - 7\].
Additional Information:
In order to check if the values of $x$ that are obtained are correct or not we simply have to substitute the values of $x$ in the given parent equation and see whether the equation is satisfied or not. If it satisfies the parent equation then the value of $x$ that we have got is correct.
Note:Quadratic formula is mainly used in conditions where grouping method cannot be used or when the polynomial cannot be reduced into some general identity. Quadratic formula method is an easier and direct method in comparison to other methods. Also while using the Quadratic formula when $\sqrt {{b^2} - 4ac} $ is a negative root then the corresponding answer would be a complex number.
Complete step by step answer:
Given
\[8{x^2} + 21 = - 59x \\
\Rightarrow 8{x^2} + 59x + 21 = 0.............................\left( i \right)\]
Now we need to compare (i) to the general formula and find the values of unknowns. Then we have to use the equation to find $x$by substituting all the values needed in it and by that way we can solve the equation\[8{x^2} + 59x + 21 = 0.\].
So on comparing (i) to the general formula$a{x^2} + bx + c = 0$, we get:
$a = 8,\;b = 59,\;c = 21.....................\left( {ii} \right)$
Now to solve for $x$we have $x = \dfrac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}......................\left( {iii} \right)$
Now substituting (ii) in (iii) we get:
\[x = \dfrac{{ - \left( {59} \right) \pm \sqrt {{{\left( {59} \right)}^2} - 4\left( {8 \times 21} \right)} }}{{2 \times 8}} \\
\Rightarrow x = \dfrac{{ - 59 \pm \sqrt {\left( {3481} \right) - 4\left( {168} \right)} }}{{16}} \\
\Rightarrow x = \dfrac{{ - 59 \pm \sqrt {\left( {3481} \right) - \left( {672} \right)} }}{{16}} \\
\Rightarrow x = \dfrac{{ - 59 \pm \sqrt {\left( {2809} \right)} }}{{16}} \\
\Rightarrow x = \dfrac{{ - 59 \pm 53}}{{16}} \\ \]
Now there are two possibilities of $x$, which is produced either by addition or by subtraction. It’s found such that:
\[x = \dfrac{{ - 59 + 53}}{{16}}\;\;\;\;{\text{and}}\;\;\;x = \dfrac{{ - 59 - 53}}{{16}} \\
\Rightarrow x = - \dfrac{6}{{16}}\;\;\;\;{\text{and}}\;\;\;x = - \dfrac{{112}}{{16}} \\
\Rightarrow x = - \dfrac{{2 \times 3}}{{2 \times 8}}\;\;\;\;{\text{and}}\;\;\;x = - \dfrac{{4 \times 4 \times 7}}{{4 \times 4}} \\
\Rightarrow x = - \dfrac{3}{8}\;\;\;\;{\text{and}}\;\;\;x = - 7 \\
\therefore x = - \dfrac{3}{8},\; - 7 \\ \]
Therefore on solving \[8{x^2} + 21 = - 59x\] we get \[x = - \dfrac{3}{8},\; - 7\].
Additional Information:
In order to check if the values of $x$ that are obtained are correct or not we simply have to substitute the values of $x$ in the given parent equation and see whether the equation is satisfied or not. If it satisfies the parent equation then the value of $x$ that we have got is correct.
Note:Quadratic formula is mainly used in conditions where grouping method cannot be used or when the polynomial cannot be reduced into some general identity. Quadratic formula method is an easier and direct method in comparison to other methods. Also while using the Quadratic formula when $\sqrt {{b^2} - 4ac} $ is a negative root then the corresponding answer would be a complex number.
Recently Updated Pages
Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Trending doubts
A number is chosen from 1 to 20 Find the probabili-class-10-maths-CBSE

Distinguish between the reserved forests and protected class 10 biology CBSE

A boat goes 24 km upstream and 28 km downstream in class 10 maths CBSE

Difference between mass and weight class 10 physics CBSE

Who gives recognition to political parties as National class 10 social science CBSE

What is oxen Plural singular plural possessive or singular class 10 english CBSE
