
How do you solve $2{x^2} - 7x + 6 = 0$ by factoring?
Answer
543.3k+ views
Hint:Use sum product method to factorize the given equation and after finding the factors, compare the factors separately with zero in order to get the solution for the equation.In sum product method, the middle term (or the term which is coefficient of “x”) is being split into two parts in such a way that their product should equals to the product of first term (or the term which is coefficient of ${x^2}$) and the constant.
Complete step by step answer:
To solve the given equation $2{x^2} - 7x + 6 = 0$ with the help of factorization, we will use the sum product method to factorize the given equation.In this method we will first split the coefficient of $x$ such that their product should equals to the product of coefficient of ${x^2}$ and the constant. We need to find the factors of the product $2 \times 6 = 12$, so that we can find suitable numbers for splitting the middle term
$12 = 2 \times 2 \times 3$
We can see that the mid-term $7$ can be split into $2 \times 2 = 4\;{\text{and}}\;3$
So splitting the mid-term, we will get
$
\Rightarrow 2{x^2} - 7x + 6 = 0 \\
\Rightarrow 2{x^2} - (4x + 3x) + 6 = 0 \\
\Rightarrow 2{x^2} - 4x - 3x + 6 = 0 \\ $
Now taking the common factors out from first two and next two terms,
$
\Rightarrow 2{x^2} - 4x - 3x + 6 = 0 \\
\Rightarrow 2x(x - 2) - 3(x - 2) = 0 \\
\Rightarrow (x - 2)(2x - 3) = 0 \\ $
We get the factors \[(x - 2)\;{\text{and}}\;(2x - 3)\]
Comparing them to $0$ separately to get the solution
$
\Rightarrow x - 2 = 0\;{\text{and}}\;2x - 3 = 0 \\
\Rightarrow x = 2\;{\text{and}}\;2x = 3 \\
\Rightarrow x = 2\;{\text{and}}\;x = \dfrac{3}{2} \\ $
$\therefore x = 2\;{\text{and}}\;x = \dfrac{3}{2}$ is the required solution for the equation $2{x^2} - 7x + 6 = 0$.
Note: If you face problems in splitting the middle term of the expression, then first find for common factors in the equation among all the terms, it will simplify the digits and make it easier for you to find the factors through the sum product method.
Complete step by step answer:
To solve the given equation $2{x^2} - 7x + 6 = 0$ with the help of factorization, we will use the sum product method to factorize the given equation.In this method we will first split the coefficient of $x$ such that their product should equals to the product of coefficient of ${x^2}$ and the constant. We need to find the factors of the product $2 \times 6 = 12$, so that we can find suitable numbers for splitting the middle term
$12 = 2 \times 2 \times 3$
We can see that the mid-term $7$ can be split into $2 \times 2 = 4\;{\text{and}}\;3$
So splitting the mid-term, we will get
$
\Rightarrow 2{x^2} - 7x + 6 = 0 \\
\Rightarrow 2{x^2} - (4x + 3x) + 6 = 0 \\
\Rightarrow 2{x^2} - 4x - 3x + 6 = 0 \\ $
Now taking the common factors out from first two and next two terms,
$
\Rightarrow 2{x^2} - 4x - 3x + 6 = 0 \\
\Rightarrow 2x(x - 2) - 3(x - 2) = 0 \\
\Rightarrow (x - 2)(2x - 3) = 0 \\ $
We get the factors \[(x - 2)\;{\text{and}}\;(2x - 3)\]
Comparing them to $0$ separately to get the solution
$
\Rightarrow x - 2 = 0\;{\text{and}}\;2x - 3 = 0 \\
\Rightarrow x = 2\;{\text{and}}\;2x = 3 \\
\Rightarrow x = 2\;{\text{and}}\;x = \dfrac{3}{2} \\ $
$\therefore x = 2\;{\text{and}}\;x = \dfrac{3}{2}$ is the required solution for the equation $2{x^2} - 7x + 6 = 0$.
Note: If you face problems in splitting the middle term of the expression, then first find for common factors in the equation among all the terms, it will simplify the digits and make it easier for you to find the factors through the sum product method.
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

