
Sodium carbonate is a basic salt because it is salt derived from:
(A) strong acid and strong base
(B) strong acid and weak base
(C) weak acid and strong base
(D) weak acid and weak base
Answer
582.6k+ views
Hint: Try dissociating the given salt and acidify the anion and add alkali to cation to get the components which reacted to form the salt. Accordingly classify them as strong or weak acid or base depending on their ability to dissociate.
Complete answer:
- Let’s have a look at the salt given in the question and write its molecular formula.
- Sodium carbonate has the molecular formula, $N{a_2}C{O_3}$
- Sodium carbonate, $N{a_2}C{O_3}$ dissociates in water to form sodium ions, $N{a^ + }$ and carbonate ions, $CO_{3}^{2-}$.
- Sodium ion is an electrophile so would readily react with hydroxyl ions to form sodium hydroxide, NaOH.
- Carbonate ion is a nucleophile so it would easily react with protons to form carbonic acid, ${{H}_{2}}C{{O}_{3}}$.
- Therefore, the acid-base reaction taking place to form sodium carbonate is given as,
\[{{H}_{2}}C{{O}_{3}}+2NaOH\to N{{a}_{2}}C{{O}_{3}}+2{{H}_{2}}O\]
- Now, we know that sodium hydroxide is a strong base and carbonic acid is a weak acid.
- Therefore, sodium carbonate is a basic salt because it is a salt derived from a weak acid and strong base.
Therefore, the correct answer is option (C) weak acid and strong base.
Note:
Remember acid-base reactions are also called neutralization reactions. Salts are products of neutralization reactions. Whenever you get such a question, break the salt and find its ions and then go backwards to find acid and base.
Complete answer:
- Let’s have a look at the salt given in the question and write its molecular formula.
- Sodium carbonate has the molecular formula, $N{a_2}C{O_3}$
- Sodium carbonate, $N{a_2}C{O_3}$ dissociates in water to form sodium ions, $N{a^ + }$ and carbonate ions, $CO_{3}^{2-}$.
- Sodium ion is an electrophile so would readily react with hydroxyl ions to form sodium hydroxide, NaOH.
- Carbonate ion is a nucleophile so it would easily react with protons to form carbonic acid, ${{H}_{2}}C{{O}_{3}}$.
- Therefore, the acid-base reaction taking place to form sodium carbonate is given as,
\[{{H}_{2}}C{{O}_{3}}+2NaOH\to N{{a}_{2}}C{{O}_{3}}+2{{H}_{2}}O\]
- Now, we know that sodium hydroxide is a strong base and carbonic acid is a weak acid.
- Therefore, sodium carbonate is a basic salt because it is a salt derived from a weak acid and strong base.
Therefore, the correct answer is option (C) weak acid and strong base.
Note:
Remember acid-base reactions are also called neutralization reactions. Salts are products of neutralization reactions. Whenever you get such a question, break the salt and find its ions and then go backwards to find acid and base.
Recently Updated Pages
The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Differentiate between action potential and resting class 12 biology CBSE

Two plane mirrors arranged at right angles to each class 12 physics CBSE

Which of the following molecules is are chiral A I class 12 chemistry CBSE

Name different types of neurons and give one function class 12 biology CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

What is 1s 2s 2p 3s 3p class 11 chemistry CBSE

Discuss the various forms of bacteria class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

An example of chemosynthetic bacteria is A E coli B class 11 biology CBSE

