
Sodium carbonate is a basic salt because it is salt derived from:
(A) strong acid and strong base
(B) strong acid and weak base
(C) weak acid and strong base
(D) weak acid and weak base
Answer
579.3k+ views
Hint: Try dissociating the given salt and acidify the anion and add alkali to cation to get the components which reacted to form the salt. Accordingly classify them as strong or weak acid or base depending on their ability to dissociate.
Complete answer:
- Let’s have a look at the salt given in the question and write its molecular formula.
- Sodium carbonate has the molecular formula, $N{a_2}C{O_3}$
- Sodium carbonate, $N{a_2}C{O_3}$ dissociates in water to form sodium ions, $N{a^ + }$ and carbonate ions, $CO_{3}^{2-}$.
- Sodium ion is an electrophile so would readily react with hydroxyl ions to form sodium hydroxide, NaOH.
- Carbonate ion is a nucleophile so it would easily react with protons to form carbonic acid, ${{H}_{2}}C{{O}_{3}}$.
- Therefore, the acid-base reaction taking place to form sodium carbonate is given as,
\[{{H}_{2}}C{{O}_{3}}+2NaOH\to N{{a}_{2}}C{{O}_{3}}+2{{H}_{2}}O\]
- Now, we know that sodium hydroxide is a strong base and carbonic acid is a weak acid.
- Therefore, sodium carbonate is a basic salt because it is a salt derived from a weak acid and strong base.
Therefore, the correct answer is option (C) weak acid and strong base.
Note:
Remember acid-base reactions are also called neutralization reactions. Salts are products of neutralization reactions. Whenever you get such a question, break the salt and find its ions and then go backwards to find acid and base.
Complete answer:
- Let’s have a look at the salt given in the question and write its molecular formula.
- Sodium carbonate has the molecular formula, $N{a_2}C{O_3}$
- Sodium carbonate, $N{a_2}C{O_3}$ dissociates in water to form sodium ions, $N{a^ + }$ and carbonate ions, $CO_{3}^{2-}$.
- Sodium ion is an electrophile so would readily react with hydroxyl ions to form sodium hydroxide, NaOH.
- Carbonate ion is a nucleophile so it would easily react with protons to form carbonic acid, ${{H}_{2}}C{{O}_{3}}$.
- Therefore, the acid-base reaction taking place to form sodium carbonate is given as,
\[{{H}_{2}}C{{O}_{3}}+2NaOH\to N{{a}_{2}}C{{O}_{3}}+2{{H}_{2}}O\]
- Now, we know that sodium hydroxide is a strong base and carbonic acid is a weak acid.
- Therefore, sodium carbonate is a basic salt because it is a salt derived from a weak acid and strong base.
Therefore, the correct answer is option (C) weak acid and strong base.
Note:
Remember acid-base reactions are also called neutralization reactions. Salts are products of neutralization reactions. Whenever you get such a question, break the salt and find its ions and then go backwards to find acid and base.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
Differentiate between an exothermic and an endothermic class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

