
$ S{O_3} $ can act as
(A) Oxidising agent
(B) Reducing agent
(C) Both a and b
(D) None
Answer
520.8k+ views
Hint :An oxidising agent gains electrons and gets reduced in a chemical reaction. A reducing agent loses electrons and it gets oxidised in a chemical reaction. A reducing agent is in one of its lowest possible oxidation states and is also called an electron donor.
Complete Step By Step Answer:
Sulphur trioxide is a chemical compound and it is represented by the chemical formula $ S{O_3} $ . It exists in a number of modifications that differ in molecular species and in crystalline form. It is colourless in its liquid form. It is a highly reactive substance and also a strong oxidising agent. It also acts as a fire hazard. It is a thermodynamically unstable compound with respect to the compound selenium dioxide. In $ S{O_3} $ sulphur is in $ + 6 $ oxidation state which is its highest oxidation state. So, it cannot be oxidized further. Hence, it acts as a strong oxidizing agent and because of this $ S{O_3} $ itself gets reduced and oxidised other compounds. $ S{O_3} $ is not used as a reducing agent as it cannot donate a lone pair of electrons. The bleaching action of sulphur is based on the oxidation.
Therefore, option A is the correct answer.
Note :
$ S{O_3} $ is used as a bleaching agent to remove the residual hydrogen peroxide or as a digesting agent to separate the pulp from lignin. It is also used as a catalyst in the oxidation reaction of sulphur dioxide to sulphur trioxide. It is used in the manufacture of photoelectric cells and also solar energy devices.
Complete Step By Step Answer:
Sulphur trioxide is a chemical compound and it is represented by the chemical formula $ S{O_3} $ . It exists in a number of modifications that differ in molecular species and in crystalline form. It is colourless in its liquid form. It is a highly reactive substance and also a strong oxidising agent. It also acts as a fire hazard. It is a thermodynamically unstable compound with respect to the compound selenium dioxide. In $ S{O_3} $ sulphur is in $ + 6 $ oxidation state which is its highest oxidation state. So, it cannot be oxidized further. Hence, it acts as a strong oxidizing agent and because of this $ S{O_3} $ itself gets reduced and oxidised other compounds. $ S{O_3} $ is not used as a reducing agent as it cannot donate a lone pair of electrons. The bleaching action of sulphur is based on the oxidation.
Therefore, option A is the correct answer.
Note :
$ S{O_3} $ is used as a bleaching agent to remove the residual hydrogen peroxide or as a digesting agent to separate the pulp from lignin. It is also used as a catalyst in the oxidation reaction of sulphur dioxide to sulphur trioxide. It is used in the manufacture of photoelectric cells and also solar energy devices.
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