Question

How do you simplify $\sin (\alpha + \beta ) + \sin (\alpha - \beta )$ ?

Answer 1

Hint: Trigonometry is that branch of mathematics that tells us the relation between the sides of a right-angled triangle that is the base, the perpendicular and the hypotenuse. All the trigonometric functions can be converted into any other trigonometric function through some identities and have great importance in mathematics and real-life too. To find the trigonometric value of large angles, there are many ways. In the given question, we will find the sine of the sum and the difference of $\alpha $ and $\beta $ by using the sum or difference identity.

Complete step-by-step solution:
We know that
$\sin (\alpha + \beta ) = \sin \alpha \cos \beta + \cos \alpha \sin \beta $ and $\sin (\alpha - \beta ) = \sin \alpha \cos \beta - \cos \alpha \sin \beta $
Using these values in the given question, we get –
$
 \Rightarrow \sin (\alpha + \beta ) - \sin (\alpha - \beta ) = \sin \alpha \cos \beta + \cos \alpha \sin \beta + \sin \alpha \cos \beta - \cos \alpha \sin \beta \\
   \Rightarrow \sin (\alpha + \beta ) - \sin (\alpha - \beta ) = 2\sin \alpha \cos \beta \\
 $
Hence, the simplified form of $\sin (\alpha + \beta ) + \sin (\alpha - \beta )$ is $2\sin \alpha \cos \beta $ .

Note: Trigonometric functions are of six types that are sine, cosine, tangent, cosecant, secant and cotangent. Sine, cosine and tangent are the main functions while cosecant, secant and cotangent are their reciprocals respectively. According to the sum identity of the sines, the sine of the sum of any two angles a and b is equal to the sum of the product of the sine of one angle (a) and the cosine of the other angle (b) and the product of the cosine of angle a and sine of angle b, that is, $\sin (a + b) = \sin a\cos b + \cos a\sin b$ , similarly the sine of the difference of any two angles a and b is equal to the difference of the product of the sine of one angle (a) and the cosine of the other angle (b) and the product of the cosine of angle a and sine of angle b, that is, $\sin (a - b) = \sin a\cos b - \cos a\sin b$ .