
How do you simplify ${\sin ^{ - 1}}\left( {\cos \left( {\dfrac{{7\pi }}{6}} \right)} \right)$
Answer
543.6k+ views
Hint: Here first we write $\dfrac{{7\pi }}{6}$ as $\left( {\pi + \dfrac{\pi }{6}} \right)$ and convert cosine into sine function and we will get the value of the given inverse function.
Formula used:
The trigonometric identities used here are:
First one is
$\cos \,\left( {\pi + a} \right)\, = \, - \cos \,a$
Second one is
$ - \cos \,a\, = \, - \sin \,\left( {\dfrac{\pi }{2} - a} \right)$
Third one is
$ - \,\sin \,a\, = \,\sin \,\left( { - a} \right)$
Complete step by step solution:
Here we can write $\cos \left( {\dfrac{{7\pi }}{6}} \right)$as $\cos \,\left( {\pi \, + \,\dfrac{\pi }{6}} \right)$
Using the trigonometric identity we can write
$\cos \,\left( {\pi \, + \,\dfrac{\pi }{6}} \right)\, = \, - \cos \,\left( {\dfrac{\pi }{6}} \right)$
Now, using the formula$ - \cos \,a\, = \, - \sin \,\left( {\dfrac{\pi }{2} - a} \right)$, we can write
$ - \cos \,\left( {\dfrac{\pi }{6}} \right)\, = \, - \sin \,\left( {\dfrac{\pi }{2} - \dfrac{\pi }{6}} \right)$
This can be simplified to $ - \,\sin \,\left( {\dfrac{\pi }{3}} \right)$
Now, using$ - \,\sin \,a\, = \,\sin \,\left( { - a} \right)$,
we can write $ - \,\sin \,\left( {\dfrac{\pi }{3}} \right)\, = \,\sin \,\left( { - \dfrac{\pi }{3}} \right)$
Hence, it can be written as ${\sin ^{ - 1}}\left( {\cos \left( {\dfrac{{7\pi }}{6}} \right)} \right)\, = \, - \dfrac{\pi }{3}$
Therefore the value of the given function is $ - \dfrac{\pi }{3}$
Note:
First we should know the different properties of the trigonometric function in order to solve the question easily. It is also important for us to keep in mind the quadrant in which all functions are positive or negative.
Trigonometric equations are those equations which contain trigonometric functions i.e. Sine, Cosine, Tangent, Cosecant, Secant and Cotangent.
A function of an angle expressed as the ratio of two of the sides of a right angle that angle is called trigonometric functions.
The sine, cosine, tangent, cotangent, secant and consent are the trigonometric functions.
There are three main functions in trigonometry i.e. Sine, Cosine and Tangent. There are certain trigonometric identities which can be stated as below:
$\sin x\, = \,\dfrac{1}{{\cos ec\,x}}$
$\cos x\, = \,\dfrac{1}{{\sec \,x}}$
$\tan x\, = \dfrac{1}{{\cot x}}$
The sine and the cosecant are the inverse of each other. The cosine and the secant are the inverse of each other. The tangent and the cotangent are inverse of each other. They all are related to each other in the special formulas which are called trigonometric identities.
Formula used:
The trigonometric identities used here are:
First one is
$\cos \,\left( {\pi + a} \right)\, = \, - \cos \,a$
Second one is
$ - \cos \,a\, = \, - \sin \,\left( {\dfrac{\pi }{2} - a} \right)$
Third one is
$ - \,\sin \,a\, = \,\sin \,\left( { - a} \right)$
Complete step by step solution:
Here we can write $\cos \left( {\dfrac{{7\pi }}{6}} \right)$as $\cos \,\left( {\pi \, + \,\dfrac{\pi }{6}} \right)$
Using the trigonometric identity we can write
$\cos \,\left( {\pi \, + \,\dfrac{\pi }{6}} \right)\, = \, - \cos \,\left( {\dfrac{\pi }{6}} \right)$
Now, using the formula$ - \cos \,a\, = \, - \sin \,\left( {\dfrac{\pi }{2} - a} \right)$, we can write
$ - \cos \,\left( {\dfrac{\pi }{6}} \right)\, = \, - \sin \,\left( {\dfrac{\pi }{2} - \dfrac{\pi }{6}} \right)$
This can be simplified to $ - \,\sin \,\left( {\dfrac{\pi }{3}} \right)$
Now, using$ - \,\sin \,a\, = \,\sin \,\left( { - a} \right)$,
we can write $ - \,\sin \,\left( {\dfrac{\pi }{3}} \right)\, = \,\sin \,\left( { - \dfrac{\pi }{3}} \right)$
Hence, it can be written as ${\sin ^{ - 1}}\left( {\cos \left( {\dfrac{{7\pi }}{6}} \right)} \right)\, = \, - \dfrac{\pi }{3}$
Therefore the value of the given function is $ - \dfrac{\pi }{3}$
Note:
First we should know the different properties of the trigonometric function in order to solve the question easily. It is also important for us to keep in mind the quadrant in which all functions are positive or negative.
Trigonometric equations are those equations which contain trigonometric functions i.e. Sine, Cosine, Tangent, Cosecant, Secant and Cotangent.
A function of an angle expressed as the ratio of two of the sides of a right angle that angle is called trigonometric functions.
The sine, cosine, tangent, cotangent, secant and consent are the trigonometric functions.
There are three main functions in trigonometry i.e. Sine, Cosine and Tangent. There are certain trigonometric identities which can be stated as below:
$\sin x\, = \,\dfrac{1}{{\cos ec\,x}}$
$\cos x\, = \,\dfrac{1}{{\sec \,x}}$
$\tan x\, = \dfrac{1}{{\cot x}}$
The sine and the cosecant are the inverse of each other. The cosine and the secant are the inverse of each other. The tangent and the cotangent are inverse of each other. They all are related to each other in the special formulas which are called trigonometric identities.
Recently Updated Pages
Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

10 examples of friction in our daily life

