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Simplify $8-\left[ \left( 2-3 \right)+4\times 3 \right]$ .

Answer
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Hint: To simplify $8-\left[ \left( 2-3 \right)+4\times 3 \right]$ , we will use the BODMAS rule. According to this rule, brackets (B) have to be simplified first followed by exponents (Order of), division (D), multiplication (M), addition (A) and subtraction (S). So firstly, we have to simplify the terms $\left( 2-3 \right)+4\times 3$ . Of these, we have to simplify $\left( 2-3 \right)$ first. Then, we have to simplify the result further using the BODMAS rule.

Complete step-by-step answer:
We have to simplify $8-\left[ \left( 2-3 \right)+4\times 3 \right]$ . We have to use the BODMAS rule. In BODMAS, B stands for brackets, O for order of (that is, exponents), D for division, M for multiplication, A for addition and S for subtraction. We have to solve an expression in the order B, O. D, M, A, S. So let us simplify the brackets first. We can see that the terms inside the bracket contain another bracket. So when we have to solve $\left( 2-3 \right)$ first.
$= 8-\left[ -1+4\times 3 \right]$
Now, according to BODMAS, multiplication comes first. So we have to multiply 4 by 3.
$= 8-\left[ -1+12 \right]$
Now, we have to subtract 1 from12.
$= 8-\left[ 11 \right]$
Let us rewrite the above result as
$= 8-11$
We have to subtract 11 from 8.
$= -3$
Hence, the value of $8-\left[ \left( 2-3 \right)+4\times 3 \right]$ is -3.

Note: Students must know the BODMAS rule, what each alphabet stands for and how to use this rule. BODMAS is also known as PEMDAS, where P stands for parenthesis (bracket), E for exponents (order of) and the rest similar to the BODMAS. Students must follow BODMAS rules to obtain a correct result.

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