Question

How do you simplify $40 + 40 \times 0 + 1$ using PEMDAS ?

Answer 1

Hint: In order to solve this question we need to know about PEMDAS. It is the acronym which helps in remembering the order of operations needed to be performed while simplifying a question. As we read PEMDAS, letter by letter from left to right we get to know that the preference or the priorities of the operators start getting lesser. We solve the operator of higher priority first, taking the operands from either of two sides of the operator and then calculating it terms by terms as per their precedence.

Complete Step by step answer:
- Rewriting the question, $40 + 40 \times 0 + 1$, we can see here are three terms. And we are supposed to simplify each term to get a single answer of each term and again simplify in the same manner until we get the single answer.
$40 + 40 \times 0 + 1$
- Using the PEMDAS, it suggests that P stands for Parentheses, E stands for Exponents, M stands for Multiplication, D stands for Division, A stands for Addition, S stands for Subtraction. So as per our given question multiplication should be performed first and thereafter Addition.
- $40 + 40 \times 0 + 1$, we now know that multiplication will be performed and any number multiplied by zero gives the answer zero.
\[40 + 0 + 1\]
- And now we should know the property of Additive Identity which suggests that any number. Added to 0, the sum is going to be the number which is added to zero. Performing the addition operation further, 41. Now we will end simplifying here as no operator left to be performed also the answer to the original question has ended in single answer “41”.

Note: While performing the simplification using PEMDAS also accepts to solve by the rule of PEMDAS. Parentheses is not an operation but can be considered as a container for operations. It's Easier but needs to be simplified carefully as the variations in the priorities can result in obtaining wrong answers. Multiplication and Division have the same equal powers in computing. Also Addition and subtraction have equal powers in computing.