Shape of $Se{{O}_{2}}$ molecule is:
a.) Triangular
b.) Angular
c.) Linear
d.) Pyramidal
Answer
583.2k+ views
Hint: The 3-D arrangement of atoms in a molecule is known as its molecular geometry. The molecular geometry includes the shape of the molecule as well as the bond length and bond angles of the molecule. All these factors help to determine the position of each atom in the geometry.
Complete step by step answer:
For $Se{{O}_{2}}$,
Se has 6 unpaired electrons and oxygen is a divalent atom.
Hybridization can be calculated by adding sigma bonds and lone pairs.
Se has 1 lone pair and form 2 sigma bond: hybridization number= 3
And hybridization will be $s{{p}^{2}}$ and the shape is angular.
The structure is mentioned below:
The correct option is option “B” . i.e. Shape of $Se{{O}_{2}}$ molecule is angular.
Additional Information .
The general formula which we use to calculate the hybridization of a molecule is
Hybridization number =$\dfrac{1}{2}\left[ V+M-C+A \right]$
Here V = the number of valence electrons of the central atom
C = charge on cation
A= charge on anion
M is the number of atoms linked to the central atom
The correct option is option “B” .
Note: The geometry and shape of a molecule can be the same or different as geometry of the molecule depends on the arrangement of lone pair and bond Pair while the shape of a molecule excludes the lone pair on the central atom. The molecular geometry includes the shape of the molecule as well as the bond length and bond angles of the molecule. All these factors help to determine the position of each atom in the geometry.
Complete step by step answer:
For $Se{{O}_{2}}$,
Se has 6 unpaired electrons and oxygen is a divalent atom.
Hybridization can be calculated by adding sigma bonds and lone pairs.
Se has 1 lone pair and form 2 sigma bond: hybridization number= 3
And hybridization will be $s{{p}^{2}}$ and the shape is angular.
The structure is mentioned below:
The correct option is option “B” . i.e. Shape of $Se{{O}_{2}}$ molecule is angular.
Additional Information .
The general formula which we use to calculate the hybridization of a molecule is
Hybridization number =$\dfrac{1}{2}\left[ V+M-C+A \right]$
Here V = the number of valence electrons of the central atom
C = charge on cation
A= charge on anion
M is the number of atoms linked to the central atom
The correct option is option “B” .
Note: The geometry and shape of a molecule can be the same or different as geometry of the molecule depends on the arrangement of lone pair and bond Pair while the shape of a molecule excludes the lone pair on the central atom. The molecular geometry includes the shape of the molecule as well as the bond length and bond angles of the molecule. All these factors help to determine the position of each atom in the geometry.
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