
Santa bought \[\dfrac{2}{5}\] metre of ribbon and Lalita bought \[\dfrac{3}{4}\]metre of ribbon. What is the total length of the ribbon they bought?
Answer
501.9k+ views
Hint: We are given two lengths of the ribbon and we need to find the total length of the ribbon. Now, in order to find the total length of the ribbon, we need to add both the lengths. We see that we are given the lengths of Fractions. Now, to add the fractions, we need to take the LCM of both the denominators and then solve for the numerator individually. We have to find the total length of both the persons, so we need to add them together.
Complete step-by-step solution:
Length of ribbon bought by Santa \[ = \dfrac{2}{5}\]metre
Length of ribbon bought by Lalita \[ = \dfrac{3}{4}\]metre
Total Length of the ribbon bought by them \[ = \]
Length of ribbon bought by Santa + Length of ribbon bought by Lalita
\[ = \dfrac{2}{5}metre + \dfrac{3}{4}metre\]
\[ = (\dfrac{2}{5} + \dfrac{3}{4})metre\]
\[ = \dfrac{{2 \times 4 + 3 \times 5}}{{20}}metre\]
\[ = \dfrac{{8 + 15}}{{20}}metre\]
\[ = \dfrac{{23}}{{20}}metre\]
\[\therefore \] Total length of the ribbon bought by them \[ = \dfrac{{23}}{{20}}metre\]
Note: We are given the lengths of the ribbon in fractions. We can convert them into decimals as well and then add them individually. We didn’t convert them into decimals but solved them in fractions only. While adding the fractions, we need to make sure that first of all we need to divide the denominator(which we wrote as the LCM of two denominators) and then multiply it with the numerator of that term. We usually forget to divide the LCM with the Denominators of both the terms.
Complete step-by-step solution:
Length of ribbon bought by Santa \[ = \dfrac{2}{5}\]metre
Length of ribbon bought by Lalita \[ = \dfrac{3}{4}\]metre
Total Length of the ribbon bought by them \[ = \]
Length of ribbon bought by Santa + Length of ribbon bought by Lalita
\[ = \dfrac{2}{5}metre + \dfrac{3}{4}metre\]
\[ = (\dfrac{2}{5} + \dfrac{3}{4})metre\]
\[ = \dfrac{{2 \times 4 + 3 \times 5}}{{20}}metre\]
\[ = \dfrac{{8 + 15}}{{20}}metre\]
\[ = \dfrac{{23}}{{20}}metre\]
\[\therefore \] Total length of the ribbon bought by them \[ = \dfrac{{23}}{{20}}metre\]
Note: We are given the lengths of the ribbon in fractions. We can convert them into decimals as well and then add them individually. We didn’t convert them into decimals but solved them in fractions only. While adding the fractions, we need to make sure that first of all we need to divide the denominator(which we wrote as the LCM of two denominators) and then multiply it with the numerator of that term. We usually forget to divide the LCM with the Denominators of both the terms.
Recently Updated Pages
Master Class 7 English: Engaging Questions & Answers for Success

Master Class 7 Maths: Engaging Questions & Answers for Success

Master Class 7 Science: Engaging Questions & Answers for Success

Class 7 Question and Answer - Your Ultimate Solutions Guide

Master Class 9 General Knowledge: Engaging Questions & Answers for Success

Master Class 9 Social Science: Engaging Questions & Answers for Success

Trending doubts
The value of 6 more than 7 is A 1 B 1 C 13 D 13 class 7 maths CBSE

Convert 200 Million dollars in rupees class 7 maths CBSE

How many lines of symmetry does a regular pentagon-class-7-maths-CBSE

List of coprime numbers from 1 to 100 class 7 maths CBSE

AIM To prepare stained temporary mount of onion peel class 7 biology CBSE

The plural of Chief is Chieves A True B False class 7 english CBSE


