Question

Round up the following upto three significant figures:
(A) $34.216$
(B) $10.4107$
(C) $0.04597$
(D) 2808

Answer 1

Hint: To answer this question, you must recall the rules for finding the number of significant figures in a given quantity. The numbers in a particular scientific or mathematical expression which points to the conviction or confidence through which one can assert a quantity are known as significant quantities.

Complete step by step solution
The number of significant figures in a quantity are those digits of value that have a meaningful power resolution in the fields of chemistry during measurements.
-The given number $34.216$ has five significant figures. Rounding off the number upto the third significant figure requires rounding off to the first decimal place. So the number $34.216$ when rounded off to three significant places will be $34.2$
-The given number $10.4107$ has six significant figures. Rounding off the number upto the third significant figure requires rounding it off to the first decimal place. So the number $10.4107$ when rounded off to the three significant figures will be $10.4$
-The given number $0.04597$ has five significant figures. Rounding off the number upto the third significant figure requires rounding it off till the third decimal place. So the number $0.04597$ when rounded off to three significant figures will be $0.046$
-The given number 2808 has four significant figures. Rounding off the number to three significant figures, we get 2810.

Note
The rules for determination of significant figures are that, all non- zero digits are significant, zeroes present between any two non- zero numbers are considered as significant, the adjacent zeroes at either side of the decimal are also significant.