Question

Rhombic sulphur is insoluble in carbon disulphide.
A. True
B. False

Answer 1

Hint: Sulphur has more allotropic forms than any other element. The two common crystalline forms are $\alpha $ or rhombic sulphur which is stable at room temperature, and $\beta $ or monoclinic sulphur which is stable above ${95.5^ \circ }C$.

Complete step by step solution:
These two forms mentioned above change reversibly with slow heating or slow cooling. Rhombic sulphur occurs naturally as large yellow crystals in volcanic areas. It has a melting point 385.8 K and specific gravity 2.06. rhombic sulphur crystals are formed on evaporating the solution of roll sulphur in $C{S_2}$. It is insoluble in water but dissolves to some extent in benzene, alcohol and ether. It is readily soluble in $C{S_2}$( carbon disulphide).
Monoclinic sulphur is prepared by melting rhombic sulphur in a dish and cooling, till the crust is formed. Two holes are made in the crust and the remaining liquid is poured out. On removing the crust, colourless needle shaped crystals of $\beta $-sulphur are formed. It is stable above 369 K and transforms into $\alpha $-sulphur below it. At 369K both the forms are stable and this temperature is transition state. Both rhombic and monoclinic sulphur have ${S_8}$ molecules which are packed to give different crystal structures. The ${S_8}$ ring in both the forms is puckered and has a crown shape.
A third modification known as $\gamma $ - monoclinic sulphur is nacreous ( looks like mother of pearl).It can be made by chilling hot concentrated solutions of S in solvents such as $C{S_2}$, toluene or EtOH.

Hence we can conclude that the above statement is false and the correct option is B.

Note:
All three forms contain puckered rings with a crown conformation, differ only in the overall packing of the rings in the crystal. This affects their densities.