
: Resonance is not exhibited by
(A) Phenol
(B) Aniline
(C) Nitrobenzene
(D) Cyclohexane
Answer
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Hint: Resonance can be observed in conjugated compounds (compounds having alternate single and multiple bonds). These resonance structures are hypothetical and this phenomenon imparts extra stability to the compound.
Complete step-by-step answer: We can define resonance effect as the delocalization of pi electrons or unshared electrons without shifting any atom.
The actual structure of compound is the resonance hybrid of various possible alternate structures that are known as resonating structures or canonical structures.
The resonance structures of a molecule have the same positions of nuclei and the same number of unpaired electrons. Due to resonance the molecule is planar.
The structures of phenol, aniline, nitrobenzene and cyclohexane are as follows-
The resonance can be observed in phenol, aniline and nitrobenzene since they have conjugation (alternate single and double bonds) in the molecule. In cyclohexane there is no conjugation. It has only single bonds in this molecule. So resonance effect is absent in cyclohexane. Moreover cyclohexane is not a planar molecule.
Additional information: All resonance structures do not contribute equally to the hybrid. Structures with more covalent bonds are more stable than those with a lesser number of covalent bonds.
There are two types of resonance effect- positive resonance effect and negative resonance effect. In a positive resonance effect, the transfer of electrons takes place away from the substituent group attached to the conjugated system. In a negative resonance effect, the transfer of electrons is towards the substituent group attached to the conjugated system.
Hence,the correct option is (D).
Note: In the given structures the group is an electron releasing group and hence shows a positive resonance effect. They donate the electrons to the ring. The nitro group is an electron withdrawing group. It withdraws electrons of the ring towards itself. So nitrobenzene shows a negative resonance effect.
Complete step-by-step answer: We can define resonance effect as the delocalization of pi electrons or unshared electrons without shifting any atom.
The actual structure of compound is the resonance hybrid of various possible alternate structures that are known as resonating structures or canonical structures.
The resonance structures of a molecule have the same positions of nuclei and the same number of unpaired electrons. Due to resonance the molecule is planar.
The structures of phenol, aniline, nitrobenzene and cyclohexane are as follows-

The resonance can be observed in phenol, aniline and nitrobenzene since they have conjugation (alternate single and double bonds) in the molecule. In cyclohexane there is no conjugation. It has only single bonds in this molecule. So resonance effect is absent in cyclohexane. Moreover cyclohexane is not a planar molecule.
Additional information: All resonance structures do not contribute equally to the hybrid. Structures with more covalent bonds are more stable than those with a lesser number of covalent bonds.
There are two types of resonance effect- positive resonance effect and negative resonance effect. In a positive resonance effect, the transfer of electrons takes place away from the substituent group attached to the conjugated system. In a negative resonance effect, the transfer of electrons is towards the substituent group attached to the conjugated system.
Hence,the correct option is (D).
Note: In the given structures the
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