Question

What is the relationship between the eV and the wavelength in meters of the energetically equivalent photons?

Answer 1

Hint : $ eV $ actually expresses energy as it is the unit of energy. Just like wavelength is related to energy, it can also be related to eV in the same way to wavelength. Wavelength may be defined as the distance amid two successive crests or troughs of a wave. It is measured in the direction of the wave.

Complete Step By Step Answer:
Energy is expressed as
 $ hc/\lambda $
 Where $ h $ is Planck’s constant
  $ c $ is velocity of light
 $ \lambda $ is the wavelength of photons .
The value of $ h $ is $ 6.626*{10^{ - 34}}Js $ . The value of velocity of light is $ 3*{10^8}m{s^{ - 1}} $ .
  $ c/\lambda $ is known as the frequency of those photons. Frequency is denoted by $ \vartheta $ .
 $ eV $ is electron-Volt. It is a unit of energy. 1eV is the extent of kinetic energy gained by an electron accelerating from rest through a potential difference of 1 volt in vacuum. 1 eV = $ 1.602*{10^{ - 19}}J $
 eV describes energy .That means $ eV = hc/\lambda $ .
 $ h*c = 1242eV/nm $
  $ \lambda = 1242/eV $
When $ \lambda $ is taken in an nm unit. This is the relation between eV and wavelength.

Note :
Wavelengths are determined by the intermediate (for instance, vacuum, air, or water) that a wave travels through from. Examples of waves are sound waves, light, water waves and periodic electrical signals in a conductor. A sound wave is a deviation in air pressure, while in light and other electromagnetic radiation the strength of the electric and the magnetic field differ. Water waves are deviations in the height of a body of water. In a crystal lattice vibration, atomic positions vary. From this, we can see that wavelength is inversely proportional to energy. That means when wavelength increases, energy will decrease. And when wavelength decreases then the energy will increase.