
Question: Number of atoms $558.5g$ $Fe$ (At.wt. of $Fe$ is $55.85gmo{l^{ - 1}}$) is:
A) Twice that in $60g$ carbon
B) $6.023 \times {10^{23}}$
C) Half that of $8g$ $He$
D) $558.5 \times 6.023 \times {10^{23}}$
Answer
574.8k+ views
Hint: By using the data given in the question one can find a conclusion and compare the options given in the question. One can analyze them in comparison to the number of atoms or the number of moles of the given option with respect to the $Fe$ atom.
Complete step by step answer:
1) As per the given data let's find out the number of moles of $Fe$ atom, as per the number of moles formula, $n = \dfrac{{{\text{Given weight in grams}}}}{{{\text{Atomic weight in grams}}}} = \dfrac{{558.5}}{{55.85}} = 10moles$
Hence, as per question data, there are ten numbers of moles $Fe$ are present.
2) Now let's analyze all options one by one, in option A $60g$ of carbon is given hence, the number of moles of carbon atoms in the $60g$ carbon is $n = \dfrac{{{\text{Given weight in grams}}}}{{{\text{Atomic weight in grams}}}} = \dfrac{{60}}{{12}} = 5$
As the number of atoms of $Fe$ is ten and the number of atoms of carbon is five it shows $Fe$ atoms are twice that of the carbon which shows option A is true.
3) In option B the Avogadro's number is given and let's compare that value with Avogadro's number of $Fe$ atoms, As one mole of $Fe$ the atom shows $6.023 \times {10^{23}}$ Avogadro's number than ten $Fe$ atoms will show as following $10 \times \;\left( {6.023 \times {{10}^{23}}} \right) = 6.023 \times {10^{24}}$ which does not match with the option B which is incorrect.
4) In option C, $8g$ of $He$ will give four moles which are not half of the ten $Fe$ atoms which shows option C as an incorrect option.
5) In option D, the total weight $Fe$ is multiplied by Avogadro's number which isn’t correct, and hence option D is also incorrect.
So, the correct answer is Option A.
Note:
The number of moles of an atom present in the total molecular weight is equal to the number of atoms present. The Avogadro's number shows the number of constituent particles present in the sample or compound with the total amount of the substance present in that sample.
Complete step by step answer:
1) As per the given data let's find out the number of moles of $Fe$ atom, as per the number of moles formula, $n = \dfrac{{{\text{Given weight in grams}}}}{{{\text{Atomic weight in grams}}}} = \dfrac{{558.5}}{{55.85}} = 10moles$
Hence, as per question data, there are ten numbers of moles $Fe$ are present.
2) Now let's analyze all options one by one, in option A $60g$ of carbon is given hence, the number of moles of carbon atoms in the $60g$ carbon is $n = \dfrac{{{\text{Given weight in grams}}}}{{{\text{Atomic weight in grams}}}} = \dfrac{{60}}{{12}} = 5$
As the number of atoms of $Fe$ is ten and the number of atoms of carbon is five it shows $Fe$ atoms are twice that of the carbon which shows option A is true.
3) In option B the Avogadro's number is given and let's compare that value with Avogadro's number of $Fe$ atoms, As one mole of $Fe$ the atom shows $6.023 \times {10^{23}}$ Avogadro's number than ten $Fe$ atoms will show as following $10 \times \;\left( {6.023 \times {{10}^{23}}} \right) = 6.023 \times {10^{24}}$ which does not match with the option B which is incorrect.
4) In option C, $8g$ of $He$ will give four moles which are not half of the ten $Fe$ atoms which shows option C as an incorrect option.
5) In option D, the total weight $Fe$ is multiplied by Avogadro's number which isn’t correct, and hence option D is also incorrect.
So, the correct answer is Option A.
Note:
The number of moles of an atom present in the total molecular weight is equal to the number of atoms present. The Avogadro's number shows the number of constituent particles present in the sample or compound with the total amount of the substance present in that sample.
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Class 11 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

