Hint: A number to be divisible by 3, the sum of all the digits should be divisible by 3.
In this question, we are supposed to form a five digit number which will be divisible by 3, and the divisibility test of 3 is the sum of digits should be divisible by 3.
Therefore, we are only going to consider 5 digits whose sum will result in a number which will be divisible by 3.
Complete step-by-step answer:
Let us observe the digits given to us, we have 0,1,2,3,4 and 5, to make a five digit number we only need 5 digits out of the given 6 digits,
Case 1: Using digits 0,1,2,4 and 5.
The number of ways in which we can arrange these 5 digits are \[ \Rightarrow 4 \times 4 \times 3 \times 2 \times 1\]
\[ \Rightarrow 96\]
Case 2: Using the digits 1,2,3,4 and 5
The number of ways in which we can arrange these 5 digits are \[ \Rightarrow 5 \times 4 \times 3 \times 2 \times 1\]
\[ \Rightarrow 120\]
Therefore, the total number of cases $= 96+120 = 216$
Therefore, Option A is the correct answer.
Note: Make sure that you do not take 0 in the first place because that will make the number a 4-digit number which will be considered wrong as we are supposed to form a 5-digit number.