Question

Product of 7986 and 548 is
(a) 135562
(b) 4376328
(c) 135862
(d) 135462

Answer 1

Hint: To find the product of given two numbers, expand the four digit number and multiply the three digit number with the expanded four digit number. Add all the values to get the total value of the product of two numbers.

Complete step-by-step answer:
We have to calculate the value of the product of numbers 7986 and 548.
To do so, we will firstly expand the four digit number and multiply the three digit number with the expanded four digit number. We can also expand the three digit number and multiply the four digit number with each of the terms of the expansion of four digit number to get the product of two numbers
On expanding 7986, we can write it as \[7986=7000+900+80+6\].
Thus, we can write \[7986\times 548\] as \[7986\times 548=7000\times 548+900\times 548+80\times 548+6\times 548\].
Now, we will individually calculate the value of each of the terms.
To calculate the value of \[7000\times 548\], we will multiply 7 by 548 and add three zeroes at the end. Thus, we have \[7000\times 548=3836000\].
To calculate the value of \[900\times 548\], we will multiply 9 by 548 and add two zeroes at the end. Thus, we have \[900\times 548=493200\].
To calculate the value of \[80\times 548\], we will multiply 8 by 548 and add one zero at the end. Thus, we have \[80\times 548=43840\].
To calculate the value of \[6\times 548\], we will multiply 6 by 548. Thus, we have \[6\times 548=3288\].
We will now add all the terms.
So, we have \[7986\times 548=7000\times 548+900\times 548+80\times 548+6\times 548=3836000+493200+43840+3288\].
Thus, we have \[7986\times 548=3836000+493200+43840+3288=4376328\].
Hence, the product of 7986 and 548 is 4376328, which is option (b).

Note: We can also solve this question by multiplying the two numbers using a long multiplication method. One must carefully calculate each of the terms and add them to avoid calculation errors.