Question

What is the pressure exerted by the woman weighing \[500N\] standing on one heel of area of $1c{m^2}$ ?

Answer 1

Hint:In order to this question, first we will rewrite the given facts and then we will convert the value of area of heel from $c{m^2}$ into ${m^2}$ as the unit of pressure in $metre$ . And then we will apply the formula of pressure in terms of force and area (as force and area is given in the question).

Complete step-by-step solution:
Given that-
Force exerted by the woman $ = 500N$
So, area on which force acts $ = 1c{m^2} = {(\dfrac{1}{{100}}m)^2} = \dfrac{1}{{10000}}{m^2}$
Now, to find the pressure, will go through its formula:-
(The physical force exerted on an object is known as pressure. The force applied per unit area is perpendicular to the surface of the objects. The force applied per unit area is perpendicular to the surface of the objects. In most cases, pressure is expressed in Pascal units, atmospheres, or pounds per square inch. If another substance exerts more force per unit area on it than vice versa, it is said to have negative pressure. The value of this substance is just the inverse of the pressure exerted by the other material.)
$
  \therefore Pressure = \dfrac{{Force}}{{Area}} = \dfrac{{500N}}{{\dfrac{1}{{10000}}{m^2}}} \\
  \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 500 \times 10000N.{m^{ - 2}} \\
  \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 5 \times {10^6}N.{m^{ - 2}} \\
 $
Hence, the pressure exerted by the woman weighing \[500N\] standing on one heel of area of $1c{m^2}$ is $5 \times {10^6}N.{m^{ - 2}}$ .

Note:Upstream valves are accidentally opened. Overpressure in the protected equipment can be caused by inadvertently opening valves placed at high pressure sources upstream. This flow can raise the equipment pressure to the upstream high-pressure source's design pressure.