Question

phosphorylation of glucose with the help of ATP and hexokinase produces
A)Glucose 1- phosphate
B)Glucose 6-phosphate
C)Glucose 1,6-bisphosphate
D)Fructose 1,6-bisphosphate

Answer 1

Hint: It is a product of gluconeogenesis and also serves as a substitute for glucose 6 phosphatase in the liver. It is the intracellular form of blood glucose. They are expressed in high levels in the liver and kidney.

Complete answer:
Glycolysis involves 9 reactions that convert glucose into pyruvate. Glucose is found in blood and it is a six-membered ring molecule and usually formed by the breakdown of carbohydrate and sugar.
-It enters the cell through a transporter protein. All the glycolytic enzymes are found in the cytosol.
-Glucose ring is phosphorylated in the first step of glycolysis. The process of the addition of a phosphate group to a molecule that is derived from the ATP is called Phosphorylation. So, one molecule of ATP has been already consumed at this point in the glycolysis process. Hexokinase acts as a catalyst in this reaction.
-Hexokinase as suggested is an enzyme that accelerates the process of the addition of phosphate of glucose. The final product of this process is a molecule called glucose -6- phosphate. The name it gets is due to the 6th carbon of the glucose across the phosphate group.

Additional Information: -The next step of glycolysis comprises the change of glucose 6 phosphate to fructose 6 phosphate and phosphoglucose isomerase enzyme acts as a catalyst for this reaction.
-The third step involves the conversion of fructose 6 phosphate to fructose 1 6 by phosphate which is similar to the reaction of step 1 of glycolysis. This second molecule of ATP gives the phosphate group and is added onto the F6P molecule.

So, the correct answer is, "Glucose 6-phosphate".

Note: -The initial process occurs in the cytosol of cells and requires glucose as well as an ATP molecule for the energy to begin the process of glycolysis.
-Hexokinases require divalent magnesium ions as a cofactor for the catalysis of reaction.