
Oxidation state of ${\rm{Mn}}$ in ${\rm{MnO}}$ is:
Answer
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Hint: As we know that, the oxidation state of an element is defined as the charge that the atoms in a compound would have. As we know that, an oxygen atom is present at the right side in the periodic table which exists in oxygen gas. It has zero charge in this state also known as oxidation state.
Complete answer
Oxidation number is also known as Oxidation state. Maximum oxidation state signifies the number of electrons a metal can donate. In the whole periodic table $ + 8$ is the maximum oxidation state shown by ${\rm{Os,Ru,}}\;{\rm{and}}\;{\rm{Xe}}$. Oxidation numbers are very useful in a lot of things. Although they are just a concept not fully correct then also they will be very useful. This concept can be utilized in solving redox equations, explaining the reactions in electrochemistry, and finding the compound in analytical and many more things.
There are different rules for finding the oxidation number for different compound and these are:
1. Oxidation number of the diatomic element is zero. For example: ${{\rm{H}}_{\rm{2}}}\;{\rm{C}}{{\rm{l}}_{\rm{2}}}$.
2. The sum of the oxidation number of neutral compounds is always zero.
3. Oxidation of halogen is generally $ - 1$ but chlorine and bromine have exceptions when they formed the compound with Fluorine.
4. Hydrogen also gives the oxidation state of $ + 1$ but some exceptions with metal hydride.
If we let the oxidation state of the ${\rm{Mn}}$ in ${\rm{MnO}}$ as x and we know that the oxidation state of oxygen is $ - 2$ and we know that the ${\rm{MnO}}$ has overall charge as zero . On substituting the value of the oxidation state of oxygen in equation$\left( 1 \right)$. We get;
$
{\rm{MnO}} = 0\\
{\rm{x}} - 2 = 0\\
{\rm{x}} = 2
$
Here we find the value of x, which is the oxidation state of ${\rm{Mn}}$.
Therefore,Oxidation state of Mn in MnO is +2
Note:
Oxidation numbers allow you to balance an equation properly and it represents the number electrons lost or gained in a reaction, when dealing with an atom to form a chemical bond.
Complete answer
Oxidation number is also known as Oxidation state. Maximum oxidation state signifies the number of electrons a metal can donate. In the whole periodic table $ + 8$ is the maximum oxidation state shown by ${\rm{Os,Ru,}}\;{\rm{and}}\;{\rm{Xe}}$. Oxidation numbers are very useful in a lot of things. Although they are just a concept not fully correct then also they will be very useful. This concept can be utilized in solving redox equations, explaining the reactions in electrochemistry, and finding the compound in analytical and many more things.
There are different rules for finding the oxidation number for different compound and these are:
1. Oxidation number of the diatomic element is zero. For example: ${{\rm{H}}_{\rm{2}}}\;{\rm{C}}{{\rm{l}}_{\rm{2}}}$.
2. The sum of the oxidation number of neutral compounds is always zero.
3. Oxidation of halogen is generally $ - 1$ but chlorine and bromine have exceptions when they formed the compound with Fluorine.
4. Hydrogen also gives the oxidation state of $ + 1$ but some exceptions with metal hydride.
If we let the oxidation state of the ${\rm{Mn}}$ in ${\rm{MnO}}$ as x and we know that the oxidation state of oxygen is $ - 2$ and we know that the ${\rm{MnO}}$ has overall charge as zero . On substituting the value of the oxidation state of oxygen in equation$\left( 1 \right)$. We get;
$
{\rm{MnO}} = 0\\
{\rm{x}} - 2 = 0\\
{\rm{x}} = 2
$
Here we find the value of x, which is the oxidation state of ${\rm{Mn}}$.
Therefore,Oxidation state of Mn in MnO is +2
Note:
Oxidation numbers allow you to balance an equation properly and it represents the number electrons lost or gained in a reaction, when dealing with an atom to form a chemical bond.
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