
Oxidation number of Oxygen in
Answer
501.9k+ views
Hint: Oxidation number can be described as the number which is allocated to elements in a chemical combination. This number is the count of electrons such that the atoms in a molecule can share, lose, or gain while forming chemical bonds with other atoms of a different element.
Complete step by step solution:
-The oxidation number of an atom can be defined as the charge that an atom appears to have on forming ionic bonds with different atoms.
-Finding the oxidation number of an atom:
The oxidation state of an atom is the number of electrons in an atom that molecule has gained or lost compared to a neutral atom. The electropositive atoms, the group I, II, III elements exhibit constant positive oxidation numbers.
-More electronegative atoms gain electrons from the less electronegative atom in a molecule and exhibit negative oxidation states and the numerical value of the oxidation state is equal to the number of electrons lost or gained.
-The oxidation number of an atom in a molecule is assigned by:
(i) Adding the constant oxidation state of other atoms or molecules or ions which are bonded.
(ii) The total oxidation state of a molecule or ion equal to the total charge of the molecule or ion. Given molecule, calculating the oxidation number of Oxygen in
The total charge of given molecule = 0
Oxidation state of = = 0
Oxidation state of Fe = +3
Let the oxidation number of oxygen = x
Then, 0 =
x = -2
Hence, Oxidation number of Oxygen in is -2.
Note: If a reaction is an oxidation an increase in oxidation state and if the reaction is reduction a decrease in oxidation state. Without the use of electron half-reactions in redox reactions, the change in the oxidation state of an element determines if it is oxidized or reduced.
Complete step by step solution:
-The oxidation number of an atom can be defined as the charge that an atom appears to have on forming ionic bonds with different atoms.
-Finding the oxidation number of an atom:
The oxidation state of an atom is the number of electrons in an atom that molecule has gained or lost compared to a neutral atom. The electropositive atoms, the group I, II, III elements exhibit constant positive oxidation numbers.
-More electronegative atoms gain electrons from the less electronegative atom in a molecule and exhibit negative oxidation states and the numerical value of the oxidation state is equal to the number of electrons lost or gained.
-The oxidation number of an atom in a molecule is assigned by:
(i) Adding the constant oxidation state of other atoms or molecules or ions which are bonded.
(ii) The total oxidation state of a molecule or ion equal to the total charge of the molecule or ion. Given molecule, calculating the oxidation number of Oxygen in
The total charge of given molecule = 0
Oxidation state of
Oxidation state of Fe = +3
Let the oxidation number of oxygen = x
Then, 0 =
x = -2
Hence, Oxidation number of Oxygen in
Note: If a reaction is an oxidation an increase in oxidation state and if the reaction is reduction a decrease in oxidation state. Without the use of electron half-reactions in redox reactions, the change in the oxidation state of an element determines if it is oxidized or reduced.
Recently Updated Pages
Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Trending doubts
Which one is a true fish A Jellyfish B Starfish C Dogfish class 11 biology CBSE

The flightless birds Rhea Kiwi and Emu respectively class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

How much is 23 kg in pounds class 11 chemistry CBSE
