Question

What is the oxidation number of nitrogen in $N{H}_{2}OH$?

Answer 1

Hint :The oxidation state is essentially the count of electrons that atoms during a molecule can share, lose or gain while forming chemical bonds with other atoms of a special element. oxidation number is additionally mentioned as oxidation state.

Complete Step By Step Answer:
Rules for Assigning Oxidation Numbers
-The convention is that the action is written first during a formula, followed by the anion.
-The oxidation state of a free element is usually 0.
-The oxidation state of a monatomic ion equals the charge of the ion.
-The usual oxidation state of hydrogen is +1.
 Let the oxidation state of N be x.
The oxidation state of H and O is +1 and -2 respectively.
 ∴ x+2(+1)+(−2)+1=0 ∴ x+2−2+1=0
∴ x=−1 Therefore, the oxidation state of nitrogen in $N{H}_{2}OH$ is −1.
Those with a charge will have lost electrons while those with a charge indicate their gained electrons. The entire oxidation numbers for all the atoms within the molecule also will equal the charge of the molecule. Neutral molecules will have a charge of zero while ions will have a positive or a charge .

Note :
Hydroxylamine is a compound with the formula NH₂OH. The pure material may be a white, unstable crystalline, hygroscopic compound. However, hydroxylamine is nearly always provided and used as a solution. It's wont to prepare oximes, a crucial functional group. The oxidation state of N in hydroxylamine, $H_{2}N-OH$ is −I.