
Out of which is an example of vinylic halide?
Answer
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Hint: As we know that, vinylic carbon is \[S{p^2}\] hybridized. In this type of molecule, the pi-bond is attached by a halogen atom present in the molecule. Actually vinyl groups are identified by the position of the double bond with the carbon atom to which a group is attached.
Complete Step by step answer: he halogen atom of benzyl halide is bonded with a hybrid carbon. There is a small amount of s-character in this carbon, but it is less electronegative. The halogen carbon with s-character quantity is \[33\;\% \], making it more electronegative than the former. Nucleophilic substitution reaction requires a high benzylic halide and is more reactive towards nucleophilic substitution reaction. Vinyl halide is more stable since the C-X bond is stronger due to more double bond character.
Allylic halide is a compound in which a halogen atom is connected to Allylic carbon. Allylic halide undergoes faster \[S{N^2}\] reaction than that of tertiary alkyl halide. The reason is simple \[S{N^2}\] reaction is a concerted step where a backside attack of nucleophilic occurs that means nucleophilic attack to the reacting C-center away from the leaving group.
This is vinylic halide.
Vinyl halide is inert towards both \[S{N^1}\] and \[S{N^2}\] mechanisms. The \[S{N^2}\] mechanism is not favoured for three reasons.
The substituent around a double bond are within the same plane, therefore an \[S{N^2}\] would give steric hindrance.
It means that the nucleophilic would have to attack a high electron density region with the double bond, including electronic repulsion.
The transition state of this \[S{N^2}\] reaction would be sp hybrid carbon which is not energetically favorable.
Note: Organic chemistry is versatile, so with some adoption a \[S{N^1}\] on a vinyl carbon is feasible. Vinyl is basically a group formed from alkene. There are two types of vinyl halide, one is substituted vinyl halide and second one is unsubstituted vinyl halide.
Vinyl halides are more stable due to the presence of double bond character C and hydrogen.
Complete Step by step answer: he halogen atom of benzyl halide is bonded with a hybrid carbon. There is a small amount of s-character in this carbon, but it is less electronegative. The halogen carbon with s-character quantity is \[33\;\% \], making it more electronegative than the former. Nucleophilic substitution reaction requires a high benzylic halide and is more reactive towards nucleophilic substitution reaction. Vinyl halide is more stable since the C-X bond is stronger due to more double bond character.
Allylic halide is a compound in which a halogen atom is connected to Allylic carbon. Allylic halide undergoes faster \[S{N^2}\] reaction than that of tertiary alkyl halide. The reason is simple \[S{N^2}\] reaction is a concerted step where a backside attack of nucleophilic occurs that means nucleophilic attack to the reacting C-center away from the leaving group.
This is vinylic halide.
Vinyl halide is inert towards both \[S{N^1}\] and \[S{N^2}\] mechanisms. The \[S{N^2}\] mechanism is not favoured for three reasons.
The substituent around a double bond are within the same plane, therefore an \[S{N^2}\] would give steric hindrance.
It means that the nucleophilic would have to attack a high electron density region with the double bond, including electronic repulsion.
The transition state of this \[S{N^2}\] reaction would be sp hybrid carbon which is not energetically favorable.
Note: Organic chemistry is versatile, so with some adoption a \[S{N^1}\] on a vinyl carbon is feasible. Vinyl is basically a group formed from alkene. There are two types of vinyl halide, one is substituted vinyl halide and second one is unsubstituted vinyl halide.
Vinyl halides are more stable due to the presence of double bond character C and hydrogen.
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