Question

One jug of sambhar is made using $\dfrac{3}{4}$kg dal. How many jugs of sambhar can be made from 6 kg of dal?

Answer 1

Hint: The unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.
While using the unitary method, we have to find the amount needed for one unit of the substance and then we multiply by the quantity provided.
For example, if 3 boxes can be filled by 12 chocolates, 1 box will be filled by 4 chocolates and hence 5 jugs will be filled by 20 chocolates. It is simply done by calculating multiplication $5 \times 4$.

Complete step by step solution:
Step 1
One jug of sambhar is made using = $\dfrac{3}{4}kg$ of dal

Step 2
Also, $\dfrac{3}{4}kg$ of dal can make = 1 jug of sambhar

Step 3
$\therefore $ 1 kg dal can make $ = 1 \div \dfrac{3}{4}$ jug of sambhar
                                                        $ = \dfrac{1}{{\dfrac{4}{3}}}$ jug of sambhar
                                                        $ = \dfrac{4}{3}$ jug of sambhar …… (1)

Step 4
Total mass of given dal = 6 kg

Step 5
     1 kg dal can make $ = \dfrac{4}{3}$ jug of sambhar (from (1))
              $ \Rightarrow $ 6 kg dal can make $ = 6 \times \dfrac{4}{3}$ jugs of sambhar
                                                         $ = 2 \times 4 = 8$ jugs of sambhar

Therefore, 8 jugs of sambhar can be made using 6 kg of dal.

Note:
While dividing two numbers, make sure their units are the same.
For example, 1 kg cannot be divided by 50 g. Kilogram should be converted into grams or gram should be in kilograms.
Kilograms is a bigger unit than grams.
To convert kilograms into grams, it is multiplied by 1000 and to convert grams into kilograms, it is divided by 1000. Some useful interconversion of units are as follows :
$1kg = 1000g$
$1g = 1000mg$
\[1g = \dfrac{1}{{1000}}kg\]
$1mg = \dfrac{1}{{1000}}g$
$1mg = \dfrac{1}{{1000 \times 1000}}kg$
Interconversion unit’s examples:
Convert 5 kilograms into grams.