: On heating $KCl{{O}_{3}}$ we get,

Answer Verified Verified
Hint: $KCl{{O}_{3}}$ is an oxidant and may explode on prolonged exposure to heat. Potassium chlorate undergoes a decomposition reaction on heating which gives an inorganic residue. The residue thus obtained is heat resistant and is a common inorganic salt.

Complete step by step answer:
$KCl{{O}_{3}}$ or potassium chlorate is a white crystalline compound which produces oxygen when heated in presence of a catalyst.
When heated in presence of a catalyst, like manganese dioxide it gives oxygen and an ionic inorganic salt, potassium chloride. The reaction is-
\[2KCl{{O}_{3}}(s)\to 2KCl(s)+3{{O}_{2}}(g)\]
As we can see from the above reaction, 2 moles of potassium chlorate gives 3 moles of oxygen gas and 2 moles of potassium chloride.
However, in absence of a catalyst, the reaction moves forward differently.
 On heating without a catalyst, potassium chlorate turns into potassium perchlorate which on further heating decomposes into oxygen and potassium chloride. The reaction is-
  & 4KCl{{O}_{3}}\to 3KCl{{O}_{4}}+KCl \\
 & KCl{{O}_{4}}\to KCl+2{{O}_{2}} \\
From the above reactions, we can say that 4 moles of potassium chlorate forms 3 moles of potassium perchlorate when heated. Each mole of potassium perchlorate gives 2 moles of oxygen and 1 mole of potassium chloride on further heating.
The final product obtained is the same in both the cases but the later reaction is more time consuming. Presence of a catalyst gives the product directly.
Therefore, it is clear from the above reactions that the correct answer is [B] $KCl+{{O}_{2}}$.

Additional information:
Potassium chlorate forms an extremely flammable mixture with combustible materials which may also be used in explosives. The mixture may ignite just by friction.

It is important to remember here that Potassium chlorate undergoes an oxidation-reduction reaction also known as red-ox reaction. Here, chlorine gets reduced and oxygen gets oxidised. Also , oxygen gas is evolved during the reaction. It is also important to remember that it does not form $KCl{{O}_{2}}$ on heating.