
What is the next number in the sequence 225, 100, 36, 9, 1 ?
(a) -7
(b) -6
(c) 0
(d) -1
Answer
602.7k+ views
Hint: First realise that all of the elements of this sequence are perfect squares of integers. Next, find the difference between the roots of these elements to find a pattern in these differences. Use this pattern to find the root of the next element and square that root to find the final answer.
Complete step-by-step answer:
In this question, we are given the sequence 225, 100, 36, 9, 1, …
We need to find the next term in this sequence.
We can see from the sequence that all of the elements of this sequence are perfect squares of integers.
225 = 15 $\times $ 15
100 = 10 $\times $ 10
36 = 6 $\times $ 6
9 = 3 $\times $ 3
1 = 1 $\times $ 1
So, following this pattern, we know that the next number will also be a perfect square.
Now, let us see the numbers whose perfect squares these elements are.
Let us write a new sequence with the roots of the elements of the original sequence to find a pattern in them.
15, 10, 6, 3, 1, …
From this sequence, we can see that:
15 – 10 = 5
10 – 6 = 4
6 – 3 = 3
3 – 1 = 2
As we can see, the difference between the consecutive numbers reduces by one after each step.
So, the difference between 1 and the root of the next element will be 1.
So the root of the next element will be: 1 – 1 = 0
The square of 0 is 0.
So, following the pattern, the next element of the sequence 225, 100, 36, 9, 1, … is 0.
Hence, option (c) is correct.
Note: In this question, you can find the answer in a shorter time also by using the options given. After the first step, we concluded that all of the elements of this sequence are perfect squares of integers and so the next element should also be a perfect square. Now, perfect squares cannot be negative. So, all the options are eliminated except option (c) which is our final answer.
Complete step-by-step answer:
In this question, we are given the sequence 225, 100, 36, 9, 1, …
We need to find the next term in this sequence.
We can see from the sequence that all of the elements of this sequence are perfect squares of integers.
225 = 15 $\times $ 15
100 = 10 $\times $ 10
36 = 6 $\times $ 6
9 = 3 $\times $ 3
1 = 1 $\times $ 1
So, following this pattern, we know that the next number will also be a perfect square.
Now, let us see the numbers whose perfect squares these elements are.
Let us write a new sequence with the roots of the elements of the original sequence to find a pattern in them.
15, 10, 6, 3, 1, …
From this sequence, we can see that:
15 – 10 = 5
10 – 6 = 4
6 – 3 = 3
3 – 1 = 2
As we can see, the difference between the consecutive numbers reduces by one after each step.
So, the difference between 1 and the root of the next element will be 1.
So the root of the next element will be: 1 – 1 = 0
The square of 0 is 0.
So, following the pattern, the next element of the sequence 225, 100, 36, 9, 1, … is 0.
Hence, option (c) is correct.
Note: In this question, you can find the answer in a shorter time also by using the options given. After the first step, we concluded that all of the elements of this sequence are perfect squares of integers and so the next element should also be a perfect square. Now, perfect squares cannot be negative. So, all the options are eliminated except option (c) which is our final answer.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 8 Maths: Engaging Questions & Answers for Success

Class 8 Question and Answer - Your Ultimate Solutions Guide

Trending doubts
Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

What is the median of the first 10 natural numbers class 10 maths CBSE

The Equation xxx + 2 is Satisfied when x is Equal to Class 10 Maths

Which of the following does not have a fundamental class 10 physics CBSE

State and prove converse of BPT Basic Proportionality class 10 maths CBSE

