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Hint: The reaction between the aqueous ammonia and hydrochloric acid will result in the formation of aqueous ammonium chloride. This can be described by a balanced chemical equation as;
\[N{{H}_{3\left( aq \right)}}+HC{{l}_{\left( aq \right)}}\to N{{H}_{4}}C{{l}_{\left( aq \right)}}\]
Complete answer:
Let us understand the concept in detail;
Hydrochloric acid is the strong acid which reacts with ammonia to produce ammonium chloride which is a soluble ionic compound. Hence, the product will also exist in the form of ions in the solution.
The stepwise description is as follows;
HCl will dissociate completely in the aqueous solution as it is a strong acid forming hydrogen and chloride ions;
\[HC{{L}_{\left( aq \right)}}\to {{H}^{+}}_{\left( aq \right)}+C{{l}^{-}}_{\left( aq \right)}\]
The ammonia will directly react with the ions to form the product;
\[N{{H}_{3\left( aq \right)}}+{{H}^{+}}_{\left( aq \right)}+C{{l}^{-}}_{\left( aq \right)}\to N{{H}_{4}}{{^{+}}_{\left( aq \right)}}+C{{l}^{-}}_{\left( aq \right)}\]
which can also be described firmly as,
\[N{{H}_{3\left( aq \right)}}+HC{{l}_{\left( aq \right)}}\to N{{H}_{4}}C{{l}_{\left( aq \right)}}\]
The net ionic equation is the equation where the spectator ions i.e. ions present on both sides of the equation are removed. Thus,
\[\begin{align}
& N{{H}_{3\left( aq \right)}}+{{H}^{+}}_{\left( aq \right)}+C{{l}^{-}}_{\left( aq \right)}\to N{{H}_{4}}{{^{+}}_{\left( aq \right)}}+C{{l}^{-}}_{\left( aq \right)} \\
& \therefore N{{H}_{3\left( aq \right)}}+{{H}^{+}}_{\left( aq \right)}\to N{{H}_{4}}{{^{+}}_{\left( aq \right)}} \\
\end{align}\]
Note:
Do note that the balanced equation is the necessity to describe any process or further solve any illustration based on the same. While balancing the chemical equation keep in mind to change the coefficients of the reactants or products. Do not change the subscripts of them, this step is wrong.
\[N{{H}_{3\left( aq \right)}}+HC{{l}_{\left( aq \right)}}\to N{{H}_{4}}C{{l}_{\left( aq \right)}}\]
Complete answer:
Let us understand the concept in detail;
Hydrochloric acid is the strong acid which reacts with ammonia to produce ammonium chloride which is a soluble ionic compound. Hence, the product will also exist in the form of ions in the solution.
The stepwise description is as follows;
HCl will dissociate completely in the aqueous solution as it is a strong acid forming hydrogen and chloride ions;
\[HC{{L}_{\left( aq \right)}}\to {{H}^{+}}_{\left( aq \right)}+C{{l}^{-}}_{\left( aq \right)}\]
The ammonia will directly react with the ions to form the product;
\[N{{H}_{3\left( aq \right)}}+{{H}^{+}}_{\left( aq \right)}+C{{l}^{-}}_{\left( aq \right)}\to N{{H}_{4}}{{^{+}}_{\left( aq \right)}}+C{{l}^{-}}_{\left( aq \right)}\]
which can also be described firmly as,
\[N{{H}_{3\left( aq \right)}}+HC{{l}_{\left( aq \right)}}\to N{{H}_{4}}C{{l}_{\left( aq \right)}}\]
The net ionic equation is the equation where the spectator ions i.e. ions present on both sides of the equation are removed. Thus,
\[\begin{align}
& N{{H}_{3\left( aq \right)}}+{{H}^{+}}_{\left( aq \right)}+C{{l}^{-}}_{\left( aq \right)}\to N{{H}_{4}}{{^{+}}_{\left( aq \right)}}+C{{l}^{-}}_{\left( aq \right)} \\
& \therefore N{{H}_{3\left( aq \right)}}+{{H}^{+}}_{\left( aq \right)}\to N{{H}_{4}}{{^{+}}_{\left( aq \right)}} \\
\end{align}\]
Note:
Do note that the balanced equation is the necessity to describe any process or further solve any illustration based on the same. While balancing the chemical equation keep in mind to change the coefficients of the reactants or products. Do not change the subscripts of them, this step is wrong.
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