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What is the n factor or valency factor of ozone during the change 2O33O2
A. 2
B. 4
C. 6
D. 8

Answer
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Hint: n factor or valency factor can be found by calculating how many equivalents of the product is formed per mole of the reactant. Thus, first we must find the number of equivalents of oxygen gas formed, and then divide it with the number of moles of the reactant to get the n factor.

Formulas used: eq.wt=Mv
Where eq.wt is the equivalent weight, M is the atomic weight and v is the valency.
N=Weq.wt
Where N is the number of equivalents and W is the given mass.

Complete step by step answer:
We are given that two moles of ozone react to give three moles of oxygen. To find the valency factor, we must first compute the number of equivalents of oxygen formed. For this, we need to first determine the equivalent weight of oxygen using the formula:
eq.wt=Mv
Where eq.wt is the equivalent weight, M is the atomic weight and v is the valency.
As we know, for oxygen, M=16g/mol and its valency is 2. Substituting these values, we get:
eq.wt=162=8g
Now we need to find the number of equivalents, which is given by the formula:
N=Weq.wt
Where N is the number of equivalents and W is the given mass.
The molecular weight of oxygen gas (O2) is (16×2)=32g/mol. Since there are three moles in the equation, given mass of oxygen, W=3×32=96g and we have found out that eq.wt=8g. Substituting these, we get:
N=968=12
Therefore, according to the reaction, two moles of O3 is equivalent to 12 O2.We need to find the number of equivalents per mole of O3 to get the n factor. Thus, we have:
Moles of O3Equivalents of O2
212
1n


Using the cross-multiplication rule, we have:
2×n=1×12
n=122=6
Thus, the n factor of ozone in this reaction is 6.

So, the correct answer is Option C .

Note: n factor of a compound is accurately defined as the number of moles of electrons gained or lost per mole of that compound. Thus, it is similar to the concept of valency of elements, and is based on the principle of equivalence. Note that n factor plays a major role in the balancing of redox reactions, as it also signifies the change in oxidation number.
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