
What must be added to the polynomial p(x) =$2{{x}^{3}}+9{{x}^{2}}-5x-15$, so that the resulting polynomial is exactly divisible by 2x + 3.
Answer
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Hint: First, realise that we must add a constant number to the polynomial p(x) so that it is exactly divisible by 2x + 3. Let c be this constant number. Then use the remainder theorem: The remainder theorem states that when a polynomial, f(x), is divided by a linear polynomial, x - a, the remainder of that division will be equivalent to f(a). using this, we get $P\left( \dfrac{-3}{2} \right)+c=0$. Now, solve for c which is our final answer.
Complete step-by-step answer:
In this question, we need to find what must be added to the polynomial p(x) =$2{{x}^{3}}+9{{x}^{2}}-5x-15$, so that the resulting polynomial is exactly divisible by 2x + 3.
The step by step explanation is given below:
We are given the polynomial p(x) =$2{{x}^{3}}+9{{x}^{2}}-5x-15$
We have to realise that we must add a constant number to the polynomial p(x) so that it is exactly divisible by 2x + 3.
Let c be the constant number which must be added to the above polynomial so that it is exactly divisible by 2x + 3.
We will use the remainder theorem.
The remainder theorem states that when a polynomial, f(x), is divided by a linear polynomial, x - a, the remainder of that division will be equivalent to f(a). In other words, if you want to evaluate the function f(x) for a given number, a, you can divide that function by x - a and your remainder will be equal to f(a).
Here, we have a = $\dfrac{-3}{2}$
Using the remainder theorem, we will have the following:
$P\left( \dfrac{-3}{2} \right)+c=0$
$2{{\left( \dfrac{-3}{2} \right)}^{3}}+9{{\left( \dfrac{-3}{2} \right)}^{2}}-5\left( \dfrac{-3}{2}
\right)-15+c=0$
$c+6=0$
$c=-6$
Hence, -6 must be added to the polynomial p(x) =$2{{x}^{3}}+9{{x}^{2}}-5x-15$, so that the resulting polynomial is exactly divisible by 2x + 3.
This is our final answer.
Note: In this question, it is very important to realise that we must add a constant number to the polynomial p(x) so that it is exactly divisible by 2x + 3 and that the remainder theorem states that when a polynomial, f(x), is divided by a linear polynomial, x - a, the remainder of that division will be equivalent to f(a).
Complete step-by-step answer:
In this question, we need to find what must be added to the polynomial p(x) =$2{{x}^{3}}+9{{x}^{2}}-5x-15$, so that the resulting polynomial is exactly divisible by 2x + 3.
The step by step explanation is given below:
We are given the polynomial p(x) =$2{{x}^{3}}+9{{x}^{2}}-5x-15$
We have to realise that we must add a constant number to the polynomial p(x) so that it is exactly divisible by 2x + 3.
Let c be the constant number which must be added to the above polynomial so that it is exactly divisible by 2x + 3.
We will use the remainder theorem.
The remainder theorem states that when a polynomial, f(x), is divided by a linear polynomial, x - a, the remainder of that division will be equivalent to f(a). In other words, if you want to evaluate the function f(x) for a given number, a, you can divide that function by x - a and your remainder will be equal to f(a).
Here, we have a = $\dfrac{-3}{2}$
Using the remainder theorem, we will have the following:
$P\left( \dfrac{-3}{2} \right)+c=0$
$2{{\left( \dfrac{-3}{2} \right)}^{3}}+9{{\left( \dfrac{-3}{2} \right)}^{2}}-5\left( \dfrac{-3}{2}
\right)-15+c=0$
$c+6=0$
$c=-6$
Hence, -6 must be added to the polynomial p(x) =$2{{x}^{3}}+9{{x}^{2}}-5x-15$, so that the resulting polynomial is exactly divisible by 2x + 3.
This is our final answer.
Note: In this question, it is very important to realise that we must add a constant number to the polynomial p(x) so that it is exactly divisible by 2x + 3 and that the remainder theorem states that when a polynomial, f(x), is divided by a linear polynomial, x - a, the remainder of that division will be equivalent to f(a).
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