
Molisch reagent is used to identify the following compound?
A. Glucose
B. Raffinose
C. D-deoxyribose
D. All of these
Answer
532.8k+ views
Hint: Molisch reagent is a reagent which is used in the identification of carbohydrates. The reaction is positive only if the carbohydrate reacts with an acid to give a reddish-purple coloured complex.
Complete step by step answer:
Molisch's test is a chemical test, used to detect the presence of carbohydrates. This test is based on the dehydration of the carbohydrate by an acid (we generally use sulphuric acid or hydrochloric acid) to produce an aldehyde, which condenses with two molecules of a phenol usually α-naphthol (other phenols such as resorcinol and thymol also give coloured products), which gives a reddish-purple coloured ring.
The procedure for Molisch’s test is –
Add 2-3 drops of Molisch’s reagent to a small amount of the analyte in a test tube.
Mix it well.
Now, add a few drops of concentrated sulfuric acid dropwise along the walls of the test tube(to facilitate the formation of a layer and to avoid mixing).
The development of a purple ring at the layer formed by the concentrated acid is a positive indication for the test.
If no purple or reddish-purple colour is formed, the given analyte does not contain any carbohydrate, and the test is therefore negative.
Amongst the given options, glucose gives a positive result for Molisch’s test. The reaction is as given below –
Therefore, the answer is option (a) – Glucose.
Additional information: Molisch’s test is named after Austrian botanist Hans Molisch.
Note: The result for Molisch’s test is positive reaction for almost all carbohydrates (exceptions include tetroses & trioses). Also, some glycoproteins and nucleic acids because they undergo hydrolysis when exposed to strong mineral acids. They react to form monosaccharides. And therefore, show a positive result for Molisch’s test.
Complete step by step answer:
Molisch's test is a chemical test, used to detect the presence of carbohydrates. This test is based on the dehydration of the carbohydrate by an acid (we generally use sulphuric acid or hydrochloric acid) to produce an aldehyde, which condenses with two molecules of a phenol usually α-naphthol (other phenols such as resorcinol and thymol also give coloured products), which gives a reddish-purple coloured ring.
The procedure for Molisch’s test is –
Add 2-3 drops of Molisch’s reagent to a small amount of the analyte in a test tube.
Mix it well.
Now, add a few drops of concentrated sulfuric acid dropwise along the walls of the test tube(to facilitate the formation of a layer and to avoid mixing).
The development of a purple ring at the layer formed by the concentrated acid is a positive indication for the test.
If no purple or reddish-purple colour is formed, the given analyte does not contain any carbohydrate, and the test is therefore negative.
Amongst the given options, glucose gives a positive result for Molisch’s test. The reaction is as given below –



Therefore, the answer is option (a) – Glucose.
Additional information: Molisch’s test is named after Austrian botanist Hans Molisch.
Note: The result for Molisch’s test is positive reaction for almost all carbohydrates (exceptions include tetroses & trioses). Also, some glycoproteins and nucleic acids because they undergo hydrolysis when exposed to strong mineral acids. They react to form monosaccharides. And therefore, show a positive result for Molisch’s test.
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