
How many moles and how many grams of NaCl are present in 250 mL of a 0.5 M NaCl solution?
(A) 0.125 mol; 7.32 g
(B) 7.32 mol; 0.125 g
(C) 0.125 mol; 0.125 g
(D) 7.32 mol; 7.32 g
Answer
570.9k+ views
Hint: Understand the type of concentration and molarity. The volume of the solution, as well as molarity, is mentioned in the question. We can find the number of moles and then eventually mass of NaCl added by using the below formula.
$\text{M = }\dfrac{\text{n}}{\text{V}}$
Where,
$M$ is the molarity of the solution
$n$ is the number of moles of solute
$V$ is the volume of the solution in litres
Complete step by step solution:
Molar concentration also is known as molarity is a measure of the concentration of a chemical species or substance, in particular of a solute in a solution. It is measured in terms of the amount of substance per unit volume of solution.
In chemistry, the most commonly used unit for molarity is moles per litre, having the unit symbol mol/L. This is also the SI unit representing molarity.
We have been provided with the values of molarity and volume of solution.
$M =$ $0.5 M$
$V =$ $0.250 L$
Substituting these values in the equation mentioned in hint, we get,
$\text{M = }\dfrac{\text{n}}{\text{V}}$
$\text{0}\text{.5 = }\dfrac{\text{n}}{0.250}$
$n =$ $0.125$ $mole$.
We know that 1 mole of any substance contains the amount of mass equal to its molar mass. So, 1 mole of NaCl has a mass of 58.5 g.
Similarly, 0.125 mole of NaCl will have a mass,
$\text{mass = }\dfrac{\text{58}\text{.5 x 0}\text{.125}}{1}$
mass = 7.32 g
From this we can conclude that the number of moles and grams of NaCl present in 250 mL of a 0.5 M NaCl solution is 0.125 and 7.32 respectively.
Therefore, the correct answer is option (A).
Note: Always remember to convert the volume of the solution into litres before substituting into the formula for molarity. This will help avoid confusion as well as errors.
$\text{M = }\dfrac{\text{n}}{\text{V}}$
Where,
$M$ is the molarity of the solution
$n$ is the number of moles of solute
$V$ is the volume of the solution in litres
Complete step by step solution:
Molar concentration also is known as molarity is a measure of the concentration of a chemical species or substance, in particular of a solute in a solution. It is measured in terms of the amount of substance per unit volume of solution.
In chemistry, the most commonly used unit for molarity is moles per litre, having the unit symbol mol/L. This is also the SI unit representing molarity.
We have been provided with the values of molarity and volume of solution.
$M =$ $0.5 M$
$V =$ $0.250 L$
Substituting these values in the equation mentioned in hint, we get,
$\text{M = }\dfrac{\text{n}}{\text{V}}$
$\text{0}\text{.5 = }\dfrac{\text{n}}{0.250}$
$n =$ $0.125$ $mole$.
We know that 1 mole of any substance contains the amount of mass equal to its molar mass. So, 1 mole of NaCl has a mass of 58.5 g.
Similarly, 0.125 mole of NaCl will have a mass,
$\text{mass = }\dfrac{\text{58}\text{.5 x 0}\text{.125}}{1}$
mass = 7.32 g
From this we can conclude that the number of moles and grams of NaCl present in 250 mL of a 0.5 M NaCl solution is 0.125 and 7.32 respectively.
Therefore, the correct answer is option (A).
Note: Always remember to convert the volume of the solution into litres before substituting into the formula for molarity. This will help avoid confusion as well as errors.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

What is Environment class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

How many squares are there in a chess board A 1296 class 11 maths CBSE

Distinguish between verbal and nonverbal communica class 11 english CBSE

The equivalent weight of Mohrs salt FeSO4 NH42SO4 6H2O class 11 chemistry CBSE

