Question

How many molecules of chlorine gas would be produced if 10.0g of aluminum chloride decomposed into aluminum precipitate and chlorine gas?

Answer 1

Hint :Chlorine is a chemical element with the atomic number 17 and the symbol Cl. It is the second-lightest of the halogens, appearing in the periodic table between fluorine and bromine, and its properties are mostly intermediate between them. At room temperature, chlorine is a yellow-green gas.

Complete Step By Step Answer:
To begin, you must write the correct BALANCED chemical reaction equation. Then you can determine how many moles of $ C{{l}_{2}} $ would be produced from the available moles of Cl in 10.0g of $ AlC{{l}_{3}} $ . Finally, using Avogadro's number, convert this value to the number of molecules.
The Avogadro constant is a proportionality factor that connects the number of constituent particles in a sample to the amount of substance in that sample. The reciprocal mole is its SI unit, and it is defined as NA= $ \text{6}\text{.02214076}\times \text{1}{{\text{0}}^{23}}mo{{l}^{-1}} $ . It is named after the Italian scientist Amedeo Avogadro.
2AlCl3→2Al+3Cl2
So, TWO moles of $ AlC{{l}_{3}} $ will produce THREE moles of $ C{{l}_{2}} $ .
The molecular weight of $ AlC{{l}_{3}} $ is 133.33g/mol, so 10.0g is 10.0/133.33 = 0.075mol
With our equation ratio of 3/2 this will produce 0.1125 mol $ C{{l}_{2}} $ .
0.1125 * 6.022 x $ {{10}^{23}} $ molecules/mole = 6.77 x $ {{10}^{22}} $ molecules of $ C{{l}_{2}} $ .
Thus, 6.77 x $ {{10}^{22}} $ molecules of chlorine gas would be produced if 10.0 g of aluminum chloride decomposed into aluminum precipitate and chlorine gas.

Note :
Stoichiometry enables us to predict the outcomes of chemical reactions. Making useful predictions is one of science's primary goals, along with the ability to explain phenomena observed in the natural world. Stoichiometry is also difficult, so lessons on work ethic, problem solving techniques, and perseverance are included. Stoichiometry allows us to connect learning about chemical reactions, compound formulas, mole calculations, and conversions.