Question

Molecular shapes of $S{{F}_{4}},\text{ }C{{F}_{4}}\text{ }and\text{ }Xe{{F}_{4}}$ and the number of lone pairs on the central atom are respectively.
A. The same, with 1, 2 and 1
B. The same, with 1, 0 and 1
C. Different, with 0, 1, and 2
D. Different, with 1, 0, and 2
E. The same, with 0, 0 and 1

Answer 1

Hint To know the structures of the inorganic compounds we should follow the VSEPR theory. VSEPR theory explains the structures of the inorganic compound based on the presence of lone pair of electrons and bond pair electrons.

Complete step by step answer:
- In the question it is given that to find that the shapes of the given molecules are same or different and also asked to find the lone pair of electrons on the central atom in the given molecules.
- The given molecules in the question are $S{{F}_{4}},\text{ }C{{F}_{4}}\text{ }and\text{ }Xe{{F}_{4}}$ .
- First we will draw the structures of the given molecules individually with a lone pair of electrons on the central atom.
- The structure of $S{{F}_{4}}$ is as follows.

- The structure of $C{{F}_{4}}$ is as follows.

- The structure of $Xe{{F}_{4}}$ is as follows.

- From the above structures we can say that the three molecules have different structures with 1, 0 and 2 lone pairs of electrons on the central atom.

- So, the correct option is D.

Note: In the $C{{F}_{4}}$ molecule there is no lone pair of electrons on the carbon that is why the shape of the molecule is tetrahedral. Coming to the structure of $S{{F}_{4}}$ the lone pair of electrons occupied at equatorial position and made the structure as trigonal bipyramidal.