Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store
seo-qna
SearchIcon
banner

What is the molecular formula for a compound that has an empirical formula of C3H7 and a molar mass of 86.2g/mol?
A. C9H21
B. C6H14
C. C3H7
D. None of the above

Answer
VerifiedVerified
491.4k+ views
like imagedislike image
Hint: In chemistry, the empirical method of a chemical compound is the best superb integer ratio of atoms present in a compound. A simple instance of this idea is that the empirical formulation of sulfur monoxide, or SO, might virtually be SO, as is the empirical system of disulfur dioxide, S2O2.
Complete step by step solution:
Let the molecular formula of the compound is (C3H7)n
Given molar mass of compound=
Molar mass of (C3H7)n=n(3×12+7)=n(43)
Then n(43)=86.2
So n=2
So, molecular formula is (C3H7)2=C6H14

So the correct answer is B.

Additional information:
Molecular formulas describe the exact number and type of atoms in a single molecule of a compound. The constituent elements are represented by their chemical symbols, and the range of atoms of every detail found in every molecule is proven as a subscript following that detail’s symbol. The molecular system expresses information about the proportions of atoms that represent a specific chemical compound, the usage of a unmarried line of chemical element symbols and numbers. Sometimes it is usually other symbols, such as parentheses, dashes, brackets, and plus and minus signs and symptoms.
For organic compounds, carbon and hydrogen are listed as the first elements inside the molecular method, and they're accompanied by means of the remaining factors in alphabetical order. For instance, for butane, the molecular system is C4H10. For ionic compounds, the cation precedes the anion in the molecular system. For instance, the molecular method of sodium fluoride is NaF.

Note:
The molecular system, alternatively, suggests the quantity of every sort of atom in a molecule. The structural method indicates the association of the molecule. It is likewise viable for special kinds of compounds to have equal empirical formulation. Samples are analyzed in particular elemental evaluation exams to determine what percentage of a selected detail the pattern is composed of.
Latest Vedantu courses for you
Grade 11 Science PCM | CBSE | SCHOOL | English
CBSE (2025-26)
calendar iconAcademic year 2025-26
language iconENGLISH
book iconUnlimited access till final school exam
tick
School Full course for CBSE students
PhysicsPhysics
ChemistryChemistry
MathsMaths
₹41,848 per year
Select and buy