
What is the molar mass of barium chloride, $BaC{l_2}$ ?
Answer
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Hint: We have to know that, barium chloride is a salt or an ionic compound comprising two sorts of components. Barium and chlorine, which add to its molar mass as per their individual molar masses and the stoichiometric number related to them.
Complete answer:
We have to know that barium chloride is an ionic salt that exists as white strong. Barium is a soluble earth metal chloride is a halogen. On disintegrating one mole of barium chloride we get one mole of barium metal and two moles of chloride particles or one more one mole of diatomic chloride gas that can be addressed as follows,
$BaC{l_{2\left( s \right)}} \to B{a_{\left( s \right)}} + 2C{l_{\left( g \right)}}$
$BaC{l_{2\left( s \right)}} \to B{a_{\left( s \right)}} + C{l_{2\left( g \right)}}$
The above response proposes that barium chloride contains one mole of barium particles and two moles of chloride molecules in a single mole of the compound. Along these lines the stoichiometric number for barium is one and chloride is two. One mole of a substance contains atoms equivalent to the Avogadro's number $\left( {6.022 \times {{10}^{23}}} \right)$ .
The molar mass of a compound is the proportion of the complete matter contained by one mole of that compound. Every iota present in the sub-atomic recipe of the compound contributes mass equivalent to its molar mass increased by its stoichiometric number.
We can discover the molar mass of barium chloride utilizing the accompanying recipe.
The molar mass of $BaC{l_2}$ = $\left( {1 \times Molar{\text{ mass of Ba}}} \right) + \left( {2 \times Molar{\text{ mass of Cl}}} \right)$
The molar mass of $BaC{l_2}$ = $\left( {1 \times 137{\text{ g/mol}}} \right) + \left( {2 \times 35.5g/mol} \right)$
Therefore,
The molar mass of $BaC{l_2}$ = $208g/mol$ .
Note:
We have to know that, one must not get confused between atomic mass and molar mass. As molar mass is measured in grams and atomic mass is measured in atomic units (amu). Atomic mass is measured according to a relative scale and it measures the mass of a single atom only.
Complete answer:
We have to know that barium chloride is an ionic salt that exists as white strong. Barium is a soluble earth metal chloride is a halogen. On disintegrating one mole of barium chloride we get one mole of barium metal and two moles of chloride particles or one more one mole of diatomic chloride gas that can be addressed as follows,
$BaC{l_{2\left( s \right)}} \to B{a_{\left( s \right)}} + 2C{l_{\left( g \right)}}$
$BaC{l_{2\left( s \right)}} \to B{a_{\left( s \right)}} + C{l_{2\left( g \right)}}$
The above response proposes that barium chloride contains one mole of barium particles and two moles of chloride molecules in a single mole of the compound. Along these lines the stoichiometric number for barium is one and chloride is two. One mole of a substance contains atoms equivalent to the Avogadro's number $\left( {6.022 \times {{10}^{23}}} \right)$ .
The molar mass of a compound is the proportion of the complete matter contained by one mole of that compound. Every iota present in the sub-atomic recipe of the compound contributes mass equivalent to its molar mass increased by its stoichiometric number.
We can discover the molar mass of barium chloride utilizing the accompanying recipe.
The molar mass of $BaC{l_2}$ = $\left( {1 \times Molar{\text{ mass of Ba}}} \right) + \left( {2 \times Molar{\text{ mass of Cl}}} \right)$
The molar mass of $BaC{l_2}$ = $\left( {1 \times 137{\text{ g/mol}}} \right) + \left( {2 \times 35.5g/mol} \right)$
Therefore,
The molar mass of $BaC{l_2}$ = $208g/mol$ .
Note:
We have to know that, one must not get confused between atomic mass and molar mass. As molar mass is measured in grams and atomic mass is measured in atomic units (amu). Atomic mass is measured according to a relative scale and it measures the mass of a single atom only.
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