Question

Mohit sold the TV for $Rs3600$ gaining one-sixth of the selling price. Find the gain (in Rs).

Answer 1

Hint:We are given that the selling price of the TV is $Rs3600$ and also then he gained one-sixth of the price. So now if it is given to find $n{\text{th}}$ part of $3600$, then it would be $Rs\dfrac{{3600}}{n}$.Using this concept we try to solve the question.

Complete step-by-step answer:
Here according to the question, we are given that Mohit sold the TV for $Rs3600$ gaining one-sixth of the selling price so we can write it as
Selling price of TV $ = Rs3600$
Now let us take any number $x$ and now if we are saying what is $n{\text{th}}$ part of$x$, then we just need to divide it by $n$. For example we have a $10m$ long rod and we need to do its two parts so each part will be $5m$. Similarly if we have to do its n parts, then each part’s length would be $\dfrac{{10}}{n}$
So if $n = 2$, then it will be $5m$ each and if $n = 4$, then it will be $2.5m$.
Similarly here Mohit gained one-sixth of the selling price
As we know that the selling price of the TV is $Rs3600$
Now if we are given to find $n{\text{th}}$ part of $3600$, then it would be $Rs\dfrac{{3600}}{n}$
To find $6{\text{th}}$ part of $3600$, then it would be = Rs$\dfrac{{3600}}{6} = Rs600$
So gain is $Rs600$

Note:Now if in question asked to find the Cost price of T.V. We use formula i.e Profit =Selling Price - Cost Price, substituting the values Cost Price = 3600-600 =Rs. 3000 we get the answer.Students have to remember the Profit and loss formula i.e Loss = Cost Price- Selling Price for solving these types of problems.