Question

“When mixture of $N{{H}_{4}}Cl$ and $NaN{{O}_{2}}$ is heated, gaseous product formed is ${{N}_{2}}$”. Answer whether the above statement is true or false. If true enter 1, else enter 0.

Answer 1

Hint: In the reaction, Ammonium ion has a positive charge and chloride ion has a negative charge, and the product is formed by a combination of Negative and positive charges. Reaction of these salts also give NaCl as a product.

Complete step by step answer: When mixture of $N{{H}_{4}}Cl$ and $NaN{{O}_{2}}$ is heated, gaseous product formed is ${{N}_{2}}$. This statement is true. The reaction is as follows:
\[N{{H}_{4}}Cl+NaN{{O}_{2}}\to {{N}_{2}}+2{{H}_{2}}O+NaCl\]
In the reaction of $N{{H}_{4}}Cl$ and $NaN{{O}_{2}}$, water and NaCl are formed as byproducts.
$N{{H}_{4}}Cl$,Ammonium Chloride is an inorganic compound.This compound is highly water-soluble and mildly acidic. It is used as fertilizers as a nitrogen source.It is also used in glue which helps to bond plywood.
$NaN{{O}_{2}}$ is an inorganic compound known as sodium Nitrite. It is a white to slightly yellowish crystalline powder that is very soluble in water and is hygroscopic.It is used as food preservative and antidote to cyanide poisoning. It has a role as an antimicrobial food preservative, an antihypertensive agent, a food antioxidant, a poison and an antidote to cyanide poisoning. It is nitrite salt and inorganic sodium salt.


Note: Subsequently ammonium nitrite being thermally unstable breaks into nitrogen and water and sodium chloride is left behind as depicted in the above equations. This is a method to prepare nitrogen in the laboratory. So final products are nitrogen, water and sodium chloride. Nitrogen and water escape from the reaction vessel as gas and steam respectively leaving behind only stable sodium chloride.