Courses
Courses for Kids
Free study material
Offline Centres
More
Store Icon
Store
seo-qna
SearchIcon
banner

What is the minimum value of F needed so that block begins to move upward on frictionless incline plane as shown
seo images

Answer
VerifiedVerified
465k+ views
1 likes
like imagedislike image
Hint: In the given question we have to find all the forces and the tension forces that work on the body M. Thus, we have to formulate a free body diagram here. Then by using the trigonometric ratios and Newton’s Law we will find the force F that is needed to move the block upwards.

Complete step by step answer:
seo images

In the given figure, it is clear that the weight Mg acts downward.By resolving the components of the weight Mg we get the vertical component is Mgcosθ and the horizontal component is Mgsinθ. The horizontal component Mgsinθ is the force that balances the tension T of the string.We can write,
T=Mgsinθ(1)

Now, resolving the components of the force F which is actually the tension in the string.
The horizontal component of the tension or force F is Fcosθ.Hence from the given diagram we get,
T=F+Fcosθ(2)
Comparing both the equations it is clear that,
F+Fcosθ=Mgsinθ
Taking F common from the left side of the equation we get,
F(1+cosθ)=Mgsinθ

From the half angle formula of the trigonometry we get,
F(2cos2θ2)=Mg(2sinθ2cosθ2)
Dividing both sides by 2cosθ2 we get,
F(cosθ2)=Mg(sinθ2)
Arranging the equation we get,
F=Mg(sinθ2cosθ2)F=Mgtanθ2

So, the minimum value of force F must be Mgtanθ2 in order to move the block upward.

Note: It must be noted that the given question stated that the plane is frictionless. If there is friction on the surface, it will oppose the motion of the body. Thus, we have calculated a force in opposite direction to the force required to move the body upwards to find the equation of the forces that balances each other.