
Mean free path depends on which of the following?
A. Size of the molecule
B. Density of the molecule
C. Diameter of the molecule
D. All of the above
Answer
527.1k+ views
Hint: From the kinetic theory of gasses it is assumed that gas contains several molecules that are in random motion and these molecules collide with each other. The average distance between two successive collisions is called the mean free path.
Formula used:
Mean free path$ = \dfrac{{kT}}{{\sqrt 2 \pi {d_m}^2\dfrac{N}{V}}}$
\[\begin{array}{*{20}{l}}
{k - Boltzmann{\text{ }}constant} \\
{T - Temperature} \\
{d - Diameter} \\
{N/V-no{\text{ }}of{\text{ }}molecules{\text{ }}per{\text{ }}unit{\text{ }}volume{\text{ }}\left( {density} \right)}
\end{array}\]
Complete step by step answer:
Mean free path$ = \dfrac{{kT}}{{\sqrt 2 \pi {d_m}^2\dfrac{N}{V}}}$
From the equation it is observed that the mean free path is directly proportional to the temperature but inversely proportional to the diameter and density of the molecule. From this relation it is understood that the mean free path depends on the diameter, size of the molecule and density of the molecule.
(A) With the increase in size of the molecule, the diameter of the molecule increases, therefore the space between the molecules decreases. This results in increased collisions and thereby decreases the mean free path.
(B) When density increases, the molecules are closer to each other. Thereby, increasing the number of collisions and resulting in decreasing mean free path
(C) With the increase in diameter of the molecule, the space between the molecules decreases. This results in increased collisions and thereby decreases the mean free path.
(D) Mean free path is affected by size, density and diameter of the molecule.
So, the correct answer is “Option D”.
Note: Mean free path is the average distance travelled by a particle between two successive collisions in a system. This collision causes a change in the direction of motion, energy and physical property of the particle. Mean free path is influenced by the density, radius of the molecule and also pressure and temperature. As the pressure increases the mean free path decreases.
Formula used:
Mean free path$ = \dfrac{{kT}}{{\sqrt 2 \pi {d_m}^2\dfrac{N}{V}}}$
\[\begin{array}{*{20}{l}}
{k - Boltzmann{\text{ }}constant} \\
{T - Temperature} \\
{d - Diameter} \\
{N/V-no{\text{ }}of{\text{ }}molecules{\text{ }}per{\text{ }}unit{\text{ }}volume{\text{ }}\left( {density} \right)}
\end{array}\]
Complete step by step answer:
Mean free path$ = \dfrac{{kT}}{{\sqrt 2 \pi {d_m}^2\dfrac{N}{V}}}$
From the equation it is observed that the mean free path is directly proportional to the temperature but inversely proportional to the diameter and density of the molecule. From this relation it is understood that the mean free path depends on the diameter, size of the molecule and density of the molecule.
(A) With the increase in size of the molecule, the diameter of the molecule increases, therefore the space between the molecules decreases. This results in increased collisions and thereby decreases the mean free path.
(B) When density increases, the molecules are closer to each other. Thereby, increasing the number of collisions and resulting in decreasing mean free path
(C) With the increase in diameter of the molecule, the space between the molecules decreases. This results in increased collisions and thereby decreases the mean free path.
(D) Mean free path is affected by size, density and diameter of the molecule.
So, the correct answer is “Option D”.
Note: Mean free path is the average distance travelled by a particle between two successive collisions in a system. This collision causes a change in the direction of motion, energy and physical property of the particle. Mean free path is influenced by the density, radius of the molecule and also pressure and temperature. As the pressure increases the mean free path decreases.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Explain zero factorial class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

What steps did the French revolutionaries take to create class 11 social science CBSE

The transition element that has lowest enthalpy of class 11 chemistry CBSE

Can anyone list 10 advantages and disadvantages of friction

