Question

What do you mean by 5 % of NaOH solution (W/V)?

Answer 1

Hint: If we know about how to calculate the strength of solution by different methods then, it would be easy for us to say what 5% of NaOH solution exactly means. The above question is based on the concept of mass by volume percentage, which means the mass of the solute (in grams) present in 100 ml of solution.

Complete step by step answer:
Before going directly into the question let’s first know about some basic things. First of all, we must know what a solution is. The solution is said to be a homogeneous mixture of two or more components. The solution can have various strengths, which can be calculated using various methods. They are:
- Volume percentage(v/v):
Volume percentage refers to the volume of solute (in ml) present in 100 ml of solution.
\[Volume\% = \dfrac{v}{v} \times 100\]
- Mass Percentage(w/w):
Mass percentage refers to the mass of solute (in gram) present in 100 g of solution.
\[Mass\% = \dfrac{w}{w} \times 100\]
- Mass by Volume Percentage(w/v):
Mass by volume percentage refers to the mass of solute (In grams) present in 100ml of solution.
\[Mass\% = \dfrac{w}{v} \times 100\]
Therefore, from Mass by Volume percentage concept we can say that 5% NaOH solution (W/V) means 5g of NaOH dissolved in 100ml of water.

Additional Information”.
Strength of the can be determined using the following relationship in quantitative volumetric analysis.
\[{V_1} \times {N_1} = {V_2} \times {N_2}\]

Note: Molarity, Normality, and Molality are the other methods for determining the strength of the solution.
- Molarity is defined as the number of moles of solute dissolved in one liter of solution. It is represented by M.
- Normality is defined as the number of gram-equivalent solutes dissolved in one liter (or 1000ml) of solution. It is represented by N.
- Molality is defined as the number of moles of solute dissolved in one kilogram of solvent. It is represented by m.